how do I measure voltage greater than 5V with arduino?












2












$begingroup$


I want to measure varying voltage with arduino and real time data plotting has to be done.
But the supply voltage will be 10V and the arduino is not supposed to have more than 5V.
Is there anyway I can solve this problem?
Do you have any recommendation for circuit design?





schematic





simulate this circuit – Schematic created using CircuitLab










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    2












    $begingroup$


    I want to measure varying voltage with arduino and real time data plotting has to be done.
    But the supply voltage will be 10V and the arduino is not supposed to have more than 5V.
    Is there anyway I can solve this problem?
    Do you have any recommendation for circuit design?





    schematic





    simulate this circuit – Schematic created using CircuitLab










    share|improve this question









    New contributor




    Michael is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$















      2












      2








      2





      $begingroup$


      I want to measure varying voltage with arduino and real time data plotting has to be done.
      But the supply voltage will be 10V and the arduino is not supposed to have more than 5V.
      Is there anyway I can solve this problem?
      Do you have any recommendation for circuit design?





      schematic





      simulate this circuit – Schematic created using CircuitLab










      share|improve this question









      New contributor




      Michael is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I want to measure varying voltage with arduino and real time data plotting has to be done.
      But the supply voltage will be 10V and the arduino is not supposed to have more than 5V.
      Is there anyway I can solve this problem?
      Do you have any recommendation for circuit design?





      schematic





      simulate this circuit – Schematic created using CircuitLab







      arduino circuit-design high-voltage voltage-measurement






      share|improve this question









      New contributor




      Michael is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      Michael is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question








      edited 2 hours ago







      Michael













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      asked 3 hours ago









      MichaelMichael

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          2 Answers
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          $begingroup$

          You can make a voltage divider (see e.g. Wikipedia: Voltage Divider





          Make sure R1 and R2 are equal, so instead of 10 V max, you get half (5V max).



          Connect Vout to an analog pin from the Arduino and use analogRead to read the voltage (0-5V).



          You have to make sure the resistors can handle the current.






          share|improve this answer











          $endgroup$





















            2












            $begingroup$

            Step down the voltage with a resistive divider and buffer it with an rail-to-rail input and output op-amp wired up as a voltage follower. This buffers the resistance in the resistive divider from the ADC so the divider resistance does not skew your ADC reading. This, in turn, lets you use high resistances in the divider so that the divider itself doesn't load down and skew your signal source. You always want a low output impedance going into a high input impedance so that the signal source is driven strongly and doesn't get loaded down which skews and distorts it.



            In your case you have a signal source driving a resistive divider, then you have a resistive divider the ADC. THerefore, you want the resistive divider to be very high relative to your signal source's output impedance, but you also want it to be very low relative to your ADC's input impedance. Without the buffer, you have to compromise between the two. The buffer works by having a ridiculously high input impedance that the divider plugs into and has a very low output impedance that drives the ADC.



            Higher resistances also reduces power consumption and heat. Using higher resistances without a buffer will also slow down the rate at which your ADC can sample and still have the reading make sense since it slows down the charging of the ADC sampling capacitor. You don't always need a buffer, but it's often a good idea.



            If you do not use an op-amp with rail-to-rail input and output, then you will have to divide the voltage down more than is necessary and will not be able to make full use of your ADC's input range.



            The op-amp can be a 5V one since the resistive divider, if sized properly to step down 10V, will never allow anything above 5V to enter the op-amp unless the 10V source itself becomes higher than 10V.



            enter image description here






            share|improve this answer










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            Toor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






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              2 Answers
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              2












              $begingroup$

              You can make a voltage divider (see e.g. Wikipedia: Voltage Divider





              Make sure R1 and R2 are equal, so instead of 10 V max, you get half (5V max).



              Connect Vout to an analog pin from the Arduino and use analogRead to read the voltage (0-5V).



              You have to make sure the resistors can handle the current.






              share|improve this answer











              $endgroup$


















                2












                $begingroup$

                You can make a voltage divider (see e.g. Wikipedia: Voltage Divider





                Make sure R1 and R2 are equal, so instead of 10 V max, you get half (5V max).



                Connect Vout to an analog pin from the Arduino and use analogRead to read the voltage (0-5V).



                You have to make sure the resistors can handle the current.






                share|improve this answer











                $endgroup$
















                  2












                  2








                  2





                  $begingroup$

                  You can make a voltage divider (see e.g. Wikipedia: Voltage Divider





                  Make sure R1 and R2 are equal, so instead of 10 V max, you get half (5V max).



                  Connect Vout to an analog pin from the Arduino and use analogRead to read the voltage (0-5V).



                  You have to make sure the resistors can handle the current.






                  share|improve this answer











                  $endgroup$



                  You can make a voltage divider (see e.g. Wikipedia: Voltage Divider





                  Make sure R1 and R2 are equal, so instead of 10 V max, you get half (5V max).



                  Connect Vout to an analog pin from the Arduino and use analogRead to read the voltage (0-5V).



                  You have to make sure the resistors can handle the current.







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited 2 hours ago

























                  answered 2 hours ago









                  Michel KeijzersMichel Keijzers

                  6,13092864




                  6,13092864

























                      2












                      $begingroup$

                      Step down the voltage with a resistive divider and buffer it with an rail-to-rail input and output op-amp wired up as a voltage follower. This buffers the resistance in the resistive divider from the ADC so the divider resistance does not skew your ADC reading. This, in turn, lets you use high resistances in the divider so that the divider itself doesn't load down and skew your signal source. You always want a low output impedance going into a high input impedance so that the signal source is driven strongly and doesn't get loaded down which skews and distorts it.



                      In your case you have a signal source driving a resistive divider, then you have a resistive divider the ADC. THerefore, you want the resistive divider to be very high relative to your signal source's output impedance, but you also want it to be very low relative to your ADC's input impedance. Without the buffer, you have to compromise between the two. The buffer works by having a ridiculously high input impedance that the divider plugs into and has a very low output impedance that drives the ADC.



                      Higher resistances also reduces power consumption and heat. Using higher resistances without a buffer will also slow down the rate at which your ADC can sample and still have the reading make sense since it slows down the charging of the ADC sampling capacitor. You don't always need a buffer, but it's often a good idea.



                      If you do not use an op-amp with rail-to-rail input and output, then you will have to divide the voltage down more than is necessary and will not be able to make full use of your ADC's input range.



                      The op-amp can be a 5V one since the resistive divider, if sized properly to step down 10V, will never allow anything above 5V to enter the op-amp unless the 10V source itself becomes higher than 10V.



                      enter image description here






                      share|improve this answer










                      New contributor




                      Toor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.






                      $endgroup$


















                        2












                        $begingroup$

                        Step down the voltage with a resistive divider and buffer it with an rail-to-rail input and output op-amp wired up as a voltage follower. This buffers the resistance in the resistive divider from the ADC so the divider resistance does not skew your ADC reading. This, in turn, lets you use high resistances in the divider so that the divider itself doesn't load down and skew your signal source. You always want a low output impedance going into a high input impedance so that the signal source is driven strongly and doesn't get loaded down which skews and distorts it.



                        In your case you have a signal source driving a resistive divider, then you have a resistive divider the ADC. THerefore, you want the resistive divider to be very high relative to your signal source's output impedance, but you also want it to be very low relative to your ADC's input impedance. Without the buffer, you have to compromise between the two. The buffer works by having a ridiculously high input impedance that the divider plugs into and has a very low output impedance that drives the ADC.



                        Higher resistances also reduces power consumption and heat. Using higher resistances without a buffer will also slow down the rate at which your ADC can sample and still have the reading make sense since it slows down the charging of the ADC sampling capacitor. You don't always need a buffer, but it's often a good idea.



                        If you do not use an op-amp with rail-to-rail input and output, then you will have to divide the voltage down more than is necessary and will not be able to make full use of your ADC's input range.



                        The op-amp can be a 5V one since the resistive divider, if sized properly to step down 10V, will never allow anything above 5V to enter the op-amp unless the 10V source itself becomes higher than 10V.



                        enter image description here






                        share|improve this answer










                        New contributor




                        Toor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                        Check out our Code of Conduct.






                        $endgroup$
















                          2












                          2








                          2





                          $begingroup$

                          Step down the voltage with a resistive divider and buffer it with an rail-to-rail input and output op-amp wired up as a voltage follower. This buffers the resistance in the resistive divider from the ADC so the divider resistance does not skew your ADC reading. This, in turn, lets you use high resistances in the divider so that the divider itself doesn't load down and skew your signal source. You always want a low output impedance going into a high input impedance so that the signal source is driven strongly and doesn't get loaded down which skews and distorts it.



                          In your case you have a signal source driving a resistive divider, then you have a resistive divider the ADC. THerefore, you want the resistive divider to be very high relative to your signal source's output impedance, but you also want it to be very low relative to your ADC's input impedance. Without the buffer, you have to compromise between the two. The buffer works by having a ridiculously high input impedance that the divider plugs into and has a very low output impedance that drives the ADC.



                          Higher resistances also reduces power consumption and heat. Using higher resistances without a buffer will also slow down the rate at which your ADC can sample and still have the reading make sense since it slows down the charging of the ADC sampling capacitor. You don't always need a buffer, but it's often a good idea.



                          If you do not use an op-amp with rail-to-rail input and output, then you will have to divide the voltage down more than is necessary and will not be able to make full use of your ADC's input range.



                          The op-amp can be a 5V one since the resistive divider, if sized properly to step down 10V, will never allow anything above 5V to enter the op-amp unless the 10V source itself becomes higher than 10V.



                          enter image description here






                          share|improve this answer










                          New contributor




                          Toor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                          Check out our Code of Conduct.






                          $endgroup$



                          Step down the voltage with a resistive divider and buffer it with an rail-to-rail input and output op-amp wired up as a voltage follower. This buffers the resistance in the resistive divider from the ADC so the divider resistance does not skew your ADC reading. This, in turn, lets you use high resistances in the divider so that the divider itself doesn't load down and skew your signal source. You always want a low output impedance going into a high input impedance so that the signal source is driven strongly and doesn't get loaded down which skews and distorts it.



                          In your case you have a signal source driving a resistive divider, then you have a resistive divider the ADC. THerefore, you want the resistive divider to be very high relative to your signal source's output impedance, but you also want it to be very low relative to your ADC's input impedance. Without the buffer, you have to compromise between the two. The buffer works by having a ridiculously high input impedance that the divider plugs into and has a very low output impedance that drives the ADC.



                          Higher resistances also reduces power consumption and heat. Using higher resistances without a buffer will also slow down the rate at which your ADC can sample and still have the reading make sense since it slows down the charging of the ADC sampling capacitor. You don't always need a buffer, but it's often a good idea.



                          If you do not use an op-amp with rail-to-rail input and output, then you will have to divide the voltage down more than is necessary and will not be able to make full use of your ADC's input range.



                          The op-amp can be a 5V one since the resistive divider, if sized properly to step down 10V, will never allow anything above 5V to enter the op-amp unless the 10V source itself becomes higher than 10V.



                          enter image description here







                          share|improve this answer










                          New contributor




                          Toor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                          Check out our Code of Conduct.









                          share|improve this answer



                          share|improve this answer








                          edited 27 mins ago





















                          New contributor




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                          answered 2 hours ago









                          ToorToor

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