How to create a cover page like this?












1















I saw my Chinese classmate reading a book whose cover page is really fancy, though I don’t know the Chinese characters on it.enter image description here
How could I create a cover page in my own classnotes like that?










share|improve this question


















  • 4





    What have you tried so far?

    – manooooh
    3 hours ago











  • There is a rather straightforward part, the graphics, which can be done with TikZ (for instance) and a part which requires familiarity with the Chinese characters. It seems to me that anyone trying to answer this will have to know TikZ and these characters.

    – marmot
    3 hours ago











  • @marmot I think these characters is book name, these characters are not important.

    – user450201
    3 hours ago











  • Thank you for a really good question. I'm going to be up all night, trying to recreate what @marmot has done.

    – GermanShepherd
    1 hour ago
















1















I saw my Chinese classmate reading a book whose cover page is really fancy, though I don’t know the Chinese characters on it.enter image description here
How could I create a cover page in my own classnotes like that?










share|improve this question


















  • 4





    What have you tried so far?

    – manooooh
    3 hours ago











  • There is a rather straightforward part, the graphics, which can be done with TikZ (for instance) and a part which requires familiarity with the Chinese characters. It seems to me that anyone trying to answer this will have to know TikZ and these characters.

    – marmot
    3 hours ago











  • @marmot I think these characters is book name, these characters are not important.

    – user450201
    3 hours ago











  • Thank you for a really good question. I'm going to be up all night, trying to recreate what @marmot has done.

    – GermanShepherd
    1 hour ago














1












1








1


2






I saw my Chinese classmate reading a book whose cover page is really fancy, though I don’t know the Chinese characters on it.enter image description here
How could I create a cover page in my own classnotes like that?










share|improve this question














I saw my Chinese classmate reading a book whose cover page is really fancy, though I don’t know the Chinese characters on it.enter image description here
How could I create a cover page in my own classnotes like that?







tikz-pgf covers bookcover






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 3 hours ago









user450201user450201

6713




6713








  • 4





    What have you tried so far?

    – manooooh
    3 hours ago











  • There is a rather straightforward part, the graphics, which can be done with TikZ (for instance) and a part which requires familiarity with the Chinese characters. It seems to me that anyone trying to answer this will have to know TikZ and these characters.

    – marmot
    3 hours ago











  • @marmot I think these characters is book name, these characters are not important.

    – user450201
    3 hours ago











  • Thank you for a really good question. I'm going to be up all night, trying to recreate what @marmot has done.

    – GermanShepherd
    1 hour ago














  • 4





    What have you tried so far?

    – manooooh
    3 hours ago











  • There is a rather straightforward part, the graphics, which can be done with TikZ (for instance) and a part which requires familiarity with the Chinese characters. It seems to me that anyone trying to answer this will have to know TikZ and these characters.

    – marmot
    3 hours ago











  • @marmot I think these characters is book name, these characters are not important.

    – user450201
    3 hours ago











  • Thank you for a really good question. I'm going to be up all night, trying to recreate what @marmot has done.

    – GermanShepherd
    1 hour ago








4




4





What have you tried so far?

– manooooh
3 hours ago





What have you tried so far?

– manooooh
3 hours ago













There is a rather straightforward part, the graphics, which can be done with TikZ (for instance) and a part which requires familiarity with the Chinese characters. It seems to me that anyone trying to answer this will have to know TikZ and these characters.

– marmot
3 hours ago





There is a rather straightforward part, the graphics, which can be done with TikZ (for instance) and a part which requires familiarity with the Chinese characters. It seems to me that anyone trying to answer this will have to know TikZ and these characters.

– marmot
3 hours ago













@marmot I think these characters is book name, these characters are not important.

– user450201
3 hours ago





@marmot I think these characters is book name, these characters are not important.

– user450201
3 hours ago













Thank you for a really good question. I'm going to be up all night, trying to recreate what @marmot has done.

– GermanShepherd
1 hour ago





Thank you for a really good question. I'm going to be up all night, trying to recreate what @marmot has done.

– GermanShepherd
1 hour ago










1 Answer
1






active

oldest

votes


















9














Can one do something like this? Yes. Most likely the curves in the upper right part are are some sort of Apollonius (Golden Ratio?) circles but I was too lazy to look them up.



documentclass{article}
usepackage{tikz}
usetikzlibrary{intersections,decorations.text}
definecolor{c1}{RGB}{62, 97, 127}
definecolor{c2}{RGB}{104, 182, 182}
definecolor{c3}{RGB}{107, 190, 190}
definecolor{c4}{RGB}{100, 172, 174}
begin{document}
thispagestyle{empty}
begin{tikzpicture}[overlay,remember picture,font=sffamilybfseries]
draw[very thick,c4,name path=big arc] ([xshift=-2mm]current page.north) arc(150:285:11)
coordinate[pos=0.225] (x0);
begin{scope}
clip ([xshift=-2mm]current page.north) arc(150:285:11) --(current page.north
east);
fill[c4!50,opacity=0.25] ([xshift=4.55cm]x0) circle (4.55);
fill[c4!50,opacity=0.25] ([xshift=3.4cm]x0) circle (3.4);
fill[c4!50,opacity=0.25] ([xshift=2.25cm]x0) circle (2.25);
draw[very thick,c4!50] (x0) arc(-90:30:6.5);
draw[very thick,c4] (x0) arc(90:-30:8.75);
draw[very thick,c4!50,name path=arc1] (x0) arc(90:-90:4.675);
draw[very thick,c4!50] (x0) arc(90:-90:2.875);
path[name intersections={of=big arc and arc1,by=x1}];
draw[very thick,c4,name path=arc2] (x1) arc(135:-20:4.75);
draw[very thick,c4!50] (x1) arc(135:-20:8.75);
path[name intersections={of=big arc and arc2,by={aux,x2}}];
draw[very thick,c4!50] (x2) arc(180:50:2.25);
end{scope}
path[decoration={text along path,text color=c4,
raise = -2.8ex,
text along path,
text = {|sffamilybfseries|02/18/2019},
text align = center,
},
decorate
] ([xshift=-2mm]current page.north) arc(150:245:11);
%
begin{scope}
path[clip,postaction={fill=c3}]
([xshift=2cm,yshift=-8cm]current page.center) rectangle ++ (4.2,7.7);
fill[c2] ([xshift=0.5cm,yshift=-8cm]current page.center)
([xshift=0.5cm,yshift=-8cm]current page.center) arc(180:60:2)
|- ++ (-3,6) --cycle;
draw[very thick,c4] ([xshift=-1.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=0.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=2.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=4.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
fill[red] ([xshift=2.5cm,yshift=-8cm]current page.center) +(60:2) circle(1.5mm)
node[above right=2mm]{$displaystylerho=frac{1+sqrt{-3}}{2}$};
end{scope}
%
fill[c1] ([xshift=2cm,yshift=-8cm]current page.center) rectangle ++ (-12.7,7.7);
node[text=white,anchor=west,scale=5,inner sep=0pt] at
([xshift=-8cm,yshift=-3.25cm]current page.center) {Some text};
node[text=white,anchor=west,scale=2.5,inner sep=0pt] at
([xshift=-8cm,yshift=-6cm]current page.center) {Some text};
%
draw[gray,line width=5mm]
([xshift=2mm,yshift=-1mm]current page.south west) rectangle ([xshift=-2mm,yshift=1mm]current
page.north east);
end{tikzpicture}
end{document}


enter image description here






share|improve this answer


























  • You’re so great!! Thanks a lot!!!

    – user450201
    2 hours ago











  • Such a nice answer...great...

    – MadyYuvi
    2 hours ago











  • sqrt{-3} I have the feeling that there is a typo on the original cover. Also, instead of using displaystyle you could use dfrac from amsmath.

    – Henri Menke
    1 hour ago











  • I don't think it's Apollonian circles, because they don't intersect: en.wikipedia.org/wiki/Apollonian_gasket

    – Henri Menke
    1 hour ago






  • 1





    @HenriMenke I believe that the cover is correct. rho is the sixth root of unity, i.e. rho=(1+sqrt{-3})/2=(1+mathrm{i}sqrt{3})/2=exp(2pimathrm{i}/6). I agree that these are not the standard Apollonius circles, which is why I wrote "some sort of Apollonius circles". While I believe to understand the inlay figure (which is the fundamental domain of the torus parameter tau with rho being the nontrivial selfdual point, I do not remember what the circles are even though I should.)

    – marmot
    1 hour ago











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1 Answer
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1 Answer
1






active

oldest

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active

oldest

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active

oldest

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9














Can one do something like this? Yes. Most likely the curves in the upper right part are are some sort of Apollonius (Golden Ratio?) circles but I was too lazy to look them up.



documentclass{article}
usepackage{tikz}
usetikzlibrary{intersections,decorations.text}
definecolor{c1}{RGB}{62, 97, 127}
definecolor{c2}{RGB}{104, 182, 182}
definecolor{c3}{RGB}{107, 190, 190}
definecolor{c4}{RGB}{100, 172, 174}
begin{document}
thispagestyle{empty}
begin{tikzpicture}[overlay,remember picture,font=sffamilybfseries]
draw[very thick,c4,name path=big arc] ([xshift=-2mm]current page.north) arc(150:285:11)
coordinate[pos=0.225] (x0);
begin{scope}
clip ([xshift=-2mm]current page.north) arc(150:285:11) --(current page.north
east);
fill[c4!50,opacity=0.25] ([xshift=4.55cm]x0) circle (4.55);
fill[c4!50,opacity=0.25] ([xshift=3.4cm]x0) circle (3.4);
fill[c4!50,opacity=0.25] ([xshift=2.25cm]x0) circle (2.25);
draw[very thick,c4!50] (x0) arc(-90:30:6.5);
draw[very thick,c4] (x0) arc(90:-30:8.75);
draw[very thick,c4!50,name path=arc1] (x0) arc(90:-90:4.675);
draw[very thick,c4!50] (x0) arc(90:-90:2.875);
path[name intersections={of=big arc and arc1,by=x1}];
draw[very thick,c4,name path=arc2] (x1) arc(135:-20:4.75);
draw[very thick,c4!50] (x1) arc(135:-20:8.75);
path[name intersections={of=big arc and arc2,by={aux,x2}}];
draw[very thick,c4!50] (x2) arc(180:50:2.25);
end{scope}
path[decoration={text along path,text color=c4,
raise = -2.8ex,
text along path,
text = {|sffamilybfseries|02/18/2019},
text align = center,
},
decorate
] ([xshift=-2mm]current page.north) arc(150:245:11);
%
begin{scope}
path[clip,postaction={fill=c3}]
([xshift=2cm,yshift=-8cm]current page.center) rectangle ++ (4.2,7.7);
fill[c2] ([xshift=0.5cm,yshift=-8cm]current page.center)
([xshift=0.5cm,yshift=-8cm]current page.center) arc(180:60:2)
|- ++ (-3,6) --cycle;
draw[very thick,c4] ([xshift=-1.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=0.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=2.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=4.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
fill[red] ([xshift=2.5cm,yshift=-8cm]current page.center) +(60:2) circle(1.5mm)
node[above right=2mm]{$displaystylerho=frac{1+sqrt{-3}}{2}$};
end{scope}
%
fill[c1] ([xshift=2cm,yshift=-8cm]current page.center) rectangle ++ (-12.7,7.7);
node[text=white,anchor=west,scale=5,inner sep=0pt] at
([xshift=-8cm,yshift=-3.25cm]current page.center) {Some text};
node[text=white,anchor=west,scale=2.5,inner sep=0pt] at
([xshift=-8cm,yshift=-6cm]current page.center) {Some text};
%
draw[gray,line width=5mm]
([xshift=2mm,yshift=-1mm]current page.south west) rectangle ([xshift=-2mm,yshift=1mm]current
page.north east);
end{tikzpicture}
end{document}


enter image description here






share|improve this answer


























  • You’re so great!! Thanks a lot!!!

    – user450201
    2 hours ago











  • Such a nice answer...great...

    – MadyYuvi
    2 hours ago











  • sqrt{-3} I have the feeling that there is a typo on the original cover. Also, instead of using displaystyle you could use dfrac from amsmath.

    – Henri Menke
    1 hour ago











  • I don't think it's Apollonian circles, because they don't intersect: en.wikipedia.org/wiki/Apollonian_gasket

    – Henri Menke
    1 hour ago






  • 1





    @HenriMenke I believe that the cover is correct. rho is the sixth root of unity, i.e. rho=(1+sqrt{-3})/2=(1+mathrm{i}sqrt{3})/2=exp(2pimathrm{i}/6). I agree that these are not the standard Apollonius circles, which is why I wrote "some sort of Apollonius circles". While I believe to understand the inlay figure (which is the fundamental domain of the torus parameter tau with rho being the nontrivial selfdual point, I do not remember what the circles are even though I should.)

    – marmot
    1 hour ago
















9














Can one do something like this? Yes. Most likely the curves in the upper right part are are some sort of Apollonius (Golden Ratio?) circles but I was too lazy to look them up.



documentclass{article}
usepackage{tikz}
usetikzlibrary{intersections,decorations.text}
definecolor{c1}{RGB}{62, 97, 127}
definecolor{c2}{RGB}{104, 182, 182}
definecolor{c3}{RGB}{107, 190, 190}
definecolor{c4}{RGB}{100, 172, 174}
begin{document}
thispagestyle{empty}
begin{tikzpicture}[overlay,remember picture,font=sffamilybfseries]
draw[very thick,c4,name path=big arc] ([xshift=-2mm]current page.north) arc(150:285:11)
coordinate[pos=0.225] (x0);
begin{scope}
clip ([xshift=-2mm]current page.north) arc(150:285:11) --(current page.north
east);
fill[c4!50,opacity=0.25] ([xshift=4.55cm]x0) circle (4.55);
fill[c4!50,opacity=0.25] ([xshift=3.4cm]x0) circle (3.4);
fill[c4!50,opacity=0.25] ([xshift=2.25cm]x0) circle (2.25);
draw[very thick,c4!50] (x0) arc(-90:30:6.5);
draw[very thick,c4] (x0) arc(90:-30:8.75);
draw[very thick,c4!50,name path=arc1] (x0) arc(90:-90:4.675);
draw[very thick,c4!50] (x0) arc(90:-90:2.875);
path[name intersections={of=big arc and arc1,by=x1}];
draw[very thick,c4,name path=arc2] (x1) arc(135:-20:4.75);
draw[very thick,c4!50] (x1) arc(135:-20:8.75);
path[name intersections={of=big arc and arc2,by={aux,x2}}];
draw[very thick,c4!50] (x2) arc(180:50:2.25);
end{scope}
path[decoration={text along path,text color=c4,
raise = -2.8ex,
text along path,
text = {|sffamilybfseries|02/18/2019},
text align = center,
},
decorate
] ([xshift=-2mm]current page.north) arc(150:245:11);
%
begin{scope}
path[clip,postaction={fill=c3}]
([xshift=2cm,yshift=-8cm]current page.center) rectangle ++ (4.2,7.7);
fill[c2] ([xshift=0.5cm,yshift=-8cm]current page.center)
([xshift=0.5cm,yshift=-8cm]current page.center) arc(180:60:2)
|- ++ (-3,6) --cycle;
draw[very thick,c4] ([xshift=-1.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=0.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=2.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=4.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
fill[red] ([xshift=2.5cm,yshift=-8cm]current page.center) +(60:2) circle(1.5mm)
node[above right=2mm]{$displaystylerho=frac{1+sqrt{-3}}{2}$};
end{scope}
%
fill[c1] ([xshift=2cm,yshift=-8cm]current page.center) rectangle ++ (-12.7,7.7);
node[text=white,anchor=west,scale=5,inner sep=0pt] at
([xshift=-8cm,yshift=-3.25cm]current page.center) {Some text};
node[text=white,anchor=west,scale=2.5,inner sep=0pt] at
([xshift=-8cm,yshift=-6cm]current page.center) {Some text};
%
draw[gray,line width=5mm]
([xshift=2mm,yshift=-1mm]current page.south west) rectangle ([xshift=-2mm,yshift=1mm]current
page.north east);
end{tikzpicture}
end{document}


enter image description here






share|improve this answer


























  • You’re so great!! Thanks a lot!!!

    – user450201
    2 hours ago











  • Such a nice answer...great...

    – MadyYuvi
    2 hours ago











  • sqrt{-3} I have the feeling that there is a typo on the original cover. Also, instead of using displaystyle you could use dfrac from amsmath.

    – Henri Menke
    1 hour ago











  • I don't think it's Apollonian circles, because they don't intersect: en.wikipedia.org/wiki/Apollonian_gasket

    – Henri Menke
    1 hour ago






  • 1





    @HenriMenke I believe that the cover is correct. rho is the sixth root of unity, i.e. rho=(1+sqrt{-3})/2=(1+mathrm{i}sqrt{3})/2=exp(2pimathrm{i}/6). I agree that these are not the standard Apollonius circles, which is why I wrote "some sort of Apollonius circles". While I believe to understand the inlay figure (which is the fundamental domain of the torus parameter tau with rho being the nontrivial selfdual point, I do not remember what the circles are even though I should.)

    – marmot
    1 hour ago














9












9








9







Can one do something like this? Yes. Most likely the curves in the upper right part are are some sort of Apollonius (Golden Ratio?) circles but I was too lazy to look them up.



documentclass{article}
usepackage{tikz}
usetikzlibrary{intersections,decorations.text}
definecolor{c1}{RGB}{62, 97, 127}
definecolor{c2}{RGB}{104, 182, 182}
definecolor{c3}{RGB}{107, 190, 190}
definecolor{c4}{RGB}{100, 172, 174}
begin{document}
thispagestyle{empty}
begin{tikzpicture}[overlay,remember picture,font=sffamilybfseries]
draw[very thick,c4,name path=big arc] ([xshift=-2mm]current page.north) arc(150:285:11)
coordinate[pos=0.225] (x0);
begin{scope}
clip ([xshift=-2mm]current page.north) arc(150:285:11) --(current page.north
east);
fill[c4!50,opacity=0.25] ([xshift=4.55cm]x0) circle (4.55);
fill[c4!50,opacity=0.25] ([xshift=3.4cm]x0) circle (3.4);
fill[c4!50,opacity=0.25] ([xshift=2.25cm]x0) circle (2.25);
draw[very thick,c4!50] (x0) arc(-90:30:6.5);
draw[very thick,c4] (x0) arc(90:-30:8.75);
draw[very thick,c4!50,name path=arc1] (x0) arc(90:-90:4.675);
draw[very thick,c4!50] (x0) arc(90:-90:2.875);
path[name intersections={of=big arc and arc1,by=x1}];
draw[very thick,c4,name path=arc2] (x1) arc(135:-20:4.75);
draw[very thick,c4!50] (x1) arc(135:-20:8.75);
path[name intersections={of=big arc and arc2,by={aux,x2}}];
draw[very thick,c4!50] (x2) arc(180:50:2.25);
end{scope}
path[decoration={text along path,text color=c4,
raise = -2.8ex,
text along path,
text = {|sffamilybfseries|02/18/2019},
text align = center,
},
decorate
] ([xshift=-2mm]current page.north) arc(150:245:11);
%
begin{scope}
path[clip,postaction={fill=c3}]
([xshift=2cm,yshift=-8cm]current page.center) rectangle ++ (4.2,7.7);
fill[c2] ([xshift=0.5cm,yshift=-8cm]current page.center)
([xshift=0.5cm,yshift=-8cm]current page.center) arc(180:60:2)
|- ++ (-3,6) --cycle;
draw[very thick,c4] ([xshift=-1.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=0.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=2.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=4.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
fill[red] ([xshift=2.5cm,yshift=-8cm]current page.center) +(60:2) circle(1.5mm)
node[above right=2mm]{$displaystylerho=frac{1+sqrt{-3}}{2}$};
end{scope}
%
fill[c1] ([xshift=2cm,yshift=-8cm]current page.center) rectangle ++ (-12.7,7.7);
node[text=white,anchor=west,scale=5,inner sep=0pt] at
([xshift=-8cm,yshift=-3.25cm]current page.center) {Some text};
node[text=white,anchor=west,scale=2.5,inner sep=0pt] at
([xshift=-8cm,yshift=-6cm]current page.center) {Some text};
%
draw[gray,line width=5mm]
([xshift=2mm,yshift=-1mm]current page.south west) rectangle ([xshift=-2mm,yshift=1mm]current
page.north east);
end{tikzpicture}
end{document}


enter image description here






share|improve this answer















Can one do something like this? Yes. Most likely the curves in the upper right part are are some sort of Apollonius (Golden Ratio?) circles but I was too lazy to look them up.



documentclass{article}
usepackage{tikz}
usetikzlibrary{intersections,decorations.text}
definecolor{c1}{RGB}{62, 97, 127}
definecolor{c2}{RGB}{104, 182, 182}
definecolor{c3}{RGB}{107, 190, 190}
definecolor{c4}{RGB}{100, 172, 174}
begin{document}
thispagestyle{empty}
begin{tikzpicture}[overlay,remember picture,font=sffamilybfseries]
draw[very thick,c4,name path=big arc] ([xshift=-2mm]current page.north) arc(150:285:11)
coordinate[pos=0.225] (x0);
begin{scope}
clip ([xshift=-2mm]current page.north) arc(150:285:11) --(current page.north
east);
fill[c4!50,opacity=0.25] ([xshift=4.55cm]x0) circle (4.55);
fill[c4!50,opacity=0.25] ([xshift=3.4cm]x0) circle (3.4);
fill[c4!50,opacity=0.25] ([xshift=2.25cm]x0) circle (2.25);
draw[very thick,c4!50] (x0) arc(-90:30:6.5);
draw[very thick,c4] (x0) arc(90:-30:8.75);
draw[very thick,c4!50,name path=arc1] (x0) arc(90:-90:4.675);
draw[very thick,c4!50] (x0) arc(90:-90:2.875);
path[name intersections={of=big arc and arc1,by=x1}];
draw[very thick,c4,name path=arc2] (x1) arc(135:-20:4.75);
draw[very thick,c4!50] (x1) arc(135:-20:8.75);
path[name intersections={of=big arc and arc2,by={aux,x2}}];
draw[very thick,c4!50] (x2) arc(180:50:2.25);
end{scope}
path[decoration={text along path,text color=c4,
raise = -2.8ex,
text along path,
text = {|sffamilybfseries|02/18/2019},
text align = center,
},
decorate
] ([xshift=-2mm]current page.north) arc(150:245:11);
%
begin{scope}
path[clip,postaction={fill=c3}]
([xshift=2cm,yshift=-8cm]current page.center) rectangle ++ (4.2,7.7);
fill[c2] ([xshift=0.5cm,yshift=-8cm]current page.center)
([xshift=0.5cm,yshift=-8cm]current page.center) arc(180:60:2)
|- ++ (-3,6) --cycle;
draw[very thick,c4] ([xshift=-1.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=0.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=2.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=4.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
fill[red] ([xshift=2.5cm,yshift=-8cm]current page.center) +(60:2) circle(1.5mm)
node[above right=2mm]{$displaystylerho=frac{1+sqrt{-3}}{2}$};
end{scope}
%
fill[c1] ([xshift=2cm,yshift=-8cm]current page.center) rectangle ++ (-12.7,7.7);
node[text=white,anchor=west,scale=5,inner sep=0pt] at
([xshift=-8cm,yshift=-3.25cm]current page.center) {Some text};
node[text=white,anchor=west,scale=2.5,inner sep=0pt] at
([xshift=-8cm,yshift=-6cm]current page.center) {Some text};
%
draw[gray,line width=5mm]
([xshift=2mm,yshift=-1mm]current page.south west) rectangle ([xshift=-2mm,yshift=1mm]current
page.north east);
end{tikzpicture}
end{document}


enter image description here







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edited 1 hour ago

























answered 2 hours ago









marmotmarmot

101k4117226




101k4117226













  • You’re so great!! Thanks a lot!!!

    – user450201
    2 hours ago











  • Such a nice answer...great...

    – MadyYuvi
    2 hours ago











  • sqrt{-3} I have the feeling that there is a typo on the original cover. Also, instead of using displaystyle you could use dfrac from amsmath.

    – Henri Menke
    1 hour ago











  • I don't think it's Apollonian circles, because they don't intersect: en.wikipedia.org/wiki/Apollonian_gasket

    – Henri Menke
    1 hour ago






  • 1





    @HenriMenke I believe that the cover is correct. rho is the sixth root of unity, i.e. rho=(1+sqrt{-3})/2=(1+mathrm{i}sqrt{3})/2=exp(2pimathrm{i}/6). I agree that these are not the standard Apollonius circles, which is why I wrote "some sort of Apollonius circles". While I believe to understand the inlay figure (which is the fundamental domain of the torus parameter tau with rho being the nontrivial selfdual point, I do not remember what the circles are even though I should.)

    – marmot
    1 hour ago



















  • You’re so great!! Thanks a lot!!!

    – user450201
    2 hours ago











  • Such a nice answer...great...

    – MadyYuvi
    2 hours ago











  • sqrt{-3} I have the feeling that there is a typo on the original cover. Also, instead of using displaystyle you could use dfrac from amsmath.

    – Henri Menke
    1 hour ago











  • I don't think it's Apollonian circles, because they don't intersect: en.wikipedia.org/wiki/Apollonian_gasket

    – Henri Menke
    1 hour ago






  • 1





    @HenriMenke I believe that the cover is correct. rho is the sixth root of unity, i.e. rho=(1+sqrt{-3})/2=(1+mathrm{i}sqrt{3})/2=exp(2pimathrm{i}/6). I agree that these are not the standard Apollonius circles, which is why I wrote "some sort of Apollonius circles". While I believe to understand the inlay figure (which is the fundamental domain of the torus parameter tau with rho being the nontrivial selfdual point, I do not remember what the circles are even though I should.)

    – marmot
    1 hour ago

















You’re so great!! Thanks a lot!!!

– user450201
2 hours ago





You’re so great!! Thanks a lot!!!

– user450201
2 hours ago













Such a nice answer...great...

– MadyYuvi
2 hours ago





Such a nice answer...great...

– MadyYuvi
2 hours ago













sqrt{-3} I have the feeling that there is a typo on the original cover. Also, instead of using displaystyle you could use dfrac from amsmath.

– Henri Menke
1 hour ago





sqrt{-3} I have the feeling that there is a typo on the original cover. Also, instead of using displaystyle you could use dfrac from amsmath.

– Henri Menke
1 hour ago













I don't think it's Apollonian circles, because they don't intersect: en.wikipedia.org/wiki/Apollonian_gasket

– Henri Menke
1 hour ago





I don't think it's Apollonian circles, because they don't intersect: en.wikipedia.org/wiki/Apollonian_gasket

– Henri Menke
1 hour ago




1




1





@HenriMenke I believe that the cover is correct. rho is the sixth root of unity, i.e. rho=(1+sqrt{-3})/2=(1+mathrm{i}sqrt{3})/2=exp(2pimathrm{i}/6). I agree that these are not the standard Apollonius circles, which is why I wrote "some sort of Apollonius circles". While I believe to understand the inlay figure (which is the fundamental domain of the torus parameter tau with rho being the nontrivial selfdual point, I do not remember what the circles are even though I should.)

– marmot
1 hour ago





@HenriMenke I believe that the cover is correct. rho is the sixth root of unity, i.e. rho=(1+sqrt{-3})/2=(1+mathrm{i}sqrt{3})/2=exp(2pimathrm{i}/6). I agree that these are not the standard Apollonius circles, which is why I wrote "some sort of Apollonius circles". While I believe to understand the inlay figure (which is the fundamental domain of the torus parameter tau with rho being the nontrivial selfdual point, I do not remember what the circles are even though I should.)

– marmot
1 hour ago


















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