Loop over an optional argument












3















I'd like to use the command foo with an optional argument to step and print the counter value iterated according to the number passed.



So, for example, foo[5] should step the counter 5 times, one by one.



(!) Note that it is not the same as stepcounter{}{5}.



MWE



documentclass{report}



newcounter{mycount}

setcounter{mycount}{0}

newcommand{foo}{stepcounter{mycount}counter is textbf{themycount}}



begin{document}

first use: foo



second use: foo



now using with option to iterate: foo[2]



medskip



textit{desired output from line above should be:}



medskip



now using with option to iterate: counter is textbf{3,4}



end{document}


enter image description here






macros counters loops







share|improve this question



























    3















    I'd like to use the command foo with an optional argument to step and print the counter value iterated according to the number passed.



    So, for example, foo[5] should step the counter 5 times, one by one.



    (!) Note that it is not the same as stepcounter{}{5}.



    MWE



    documentclass{report}
    

    
newcounter{mycount}
    
setcounter{mycount}{0}
    
newcommand{foo}{stepcounter{mycount}counter is textbf{themycount}}
    

    
begin{document}
    
first use: foo
    

    
second use: foo
    

    
now using with option to iterate: foo[2]
    

    
medskip
    

    
textit{desired output from line above should be:}
    

    
medskip
    

    
now using with option to iterate: counter is textbf{3,4}
    

    
end{document}


    enter image description here






    macros counters loops







    share|improve this question

























      3












      3








      3








      I'd like to use the command foo with an optional argument to step and print the counter value iterated according to the number passed.



      So, for example, foo[5] should step the counter 5 times, one by one.



      (!) Note that it is not the same as stepcounter{}{5}.



      MWE



      documentclass{report}
      

      
newcounter{mycount}
      
setcounter{mycount}{0}
      
newcommand{foo}{stepcounter{mycount}counter is textbf{themycount}}
      

      
begin{document}
      
first use: foo
      

      
second use: foo
      

      
now using with option to iterate: foo[2]
      

      
medskip
      

      
textit{desired output from line above should be:}
      

      
medskip
      

      
now using with option to iterate: counter is textbf{3,4}
      

      
end{document}


      enter image description here






      macros counters loops







      share|improve this question














      I'd like to use the command foo with an optional argument to step and print the counter value iterated according to the number passed.



      So, for example, foo[5] should step the counter 5 times, one by one.



      (!) Note that it is not the same as stepcounter{}{5}.



      MWE



      documentclass{report}
      

      
newcounter{mycount}
      
setcounter{mycount}{0}
      
newcommand{foo}{stepcounter{mycount}counter is textbf{themycount}}
      

      
begin{document}
      
first use: foo
      

      
second use: foo
      

      
now using with option to iterate: foo[2]
      

      
medskip
      

      
textit{desired output from line above should be:}
      

      
medskip
      

      
now using with option to iterate: counter is textbf{3,4}
      

      
end{document}


      enter image description here






      macros counters loops




      macros counters loops






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 35 mins ago









      SigurSigur

      24.5k355138




      24.5k355138






















          2 Answers
          2






          active

          oldest

          votes


















          3














          With expl3 it's just a few lines.



          documentclass{report}
          
usepackage{xparse}
          

          
newcounter{mycount}
          
setcounter{mycount}{0}
          

          
ExplSyntaxOn
          
NewDocumentCommand{foo}{O{1}}
          
 {
          
  int_compare:nT { #1 > 0 }
          
   {
          
    int_compare:nTF { #1 = 1 } {counter~is} {counters~are}~
          
    stepcounter{mycount}
          
    textbf{themycount}
          
    prg_replicate:nn { #1 - 1 } {,stepcounter{mycount}textbf{themycount}}
          
   }
          
 }
          
ExplSyntaxOff
          

          
begin{document}
          
first use: foo
          

          
second use: foo
          

          
now using with option to iterate: foo[2]
          

          
now using with option to iterate: counters are textbf{3,4}
          

          
foo[5]
          

          
end{document}


          The trick is to do the first iteration and then proceed again adding first a comma.



          If the number passed is zero or less nothing happens.



          enter image description here






          share|improve this answer


























          • Exactly what I need.

            – Sigur
            24 mins ago











          • Do you think is it possible to change the text also if there is argument? I mean, to print counters are 5,6,7,8 for example.

            – Sigur
            23 mins ago











          • @Sigur Your wish is my command. Updated.

            – egreg
            17 mins ago











          • Oh, I think I should learn about NewDocumentCommand as soon as possible. Amazing and powerful.

            – Sigur
            12 mins ago



















          1














          Here is an approach using multido for looping and a delayed delimiter definition:



          enter image description here



          documentclass{article}
          

          
usepackage{multido}
          

          
newcounter{mycount}
          

          
newcommand{foo}[1][1]{%
          
  counter%
          
  ifnum#1>1relax s areelse space isfi
          
  space
          
  % https://tex.stackexchange.com/a/89187/5764
          
  defitemdelim{unskipspacedefitemdelim{,space}}% Item delimiter delayed by one cycle
          
  {bfseriesmultido{i=1+1}{#1}{itemdelim stepcounter{mycount}themycount}}%
          
}
          

          
begin{document}
          

          
first use: foo
          

          
second use: foo
          

          
now using with option to iterate: foo[2]
          

          
medskip
          

          
textit{desired output from line above should be:}
          

          
medskip
          

          
now using with option to iterate: counters are textbf{3, 4}
          

          
end{document}





          share|improve this answer
























          • This solution is more understandable to me... but I had never done it by myself. Very nice.

            – Sigur
            9 mins ago











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          2 Answers
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          active

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          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          3














          With expl3 it's just a few lines.



          documentclass{report}
          
usepackage{xparse}
          

          
newcounter{mycount}
          
setcounter{mycount}{0}
          

          
ExplSyntaxOn
          
NewDocumentCommand{foo}{O{1}}
          
 {
          
  int_compare:nT { #1 > 0 }
          
   {
          
    int_compare:nTF { #1 = 1 } {counter~is} {counters~are}~
          
    stepcounter{mycount}
          
    textbf{themycount}
          
    prg_replicate:nn { #1 - 1 } {,stepcounter{mycount}textbf{themycount}}
          
   }
          
 }
          
ExplSyntaxOff
          

          
begin{document}
          
first use: foo
          

          
second use: foo
          

          
now using with option to iterate: foo[2]
          

          
now using with option to iterate: counters are textbf{3,4}
          

          
foo[5]
          

          
end{document}


          The trick is to do the first iteration and then proceed again adding first a comma.



          If the number passed is zero or less nothing happens.



          enter image description here






          share|improve this answer


























          • Exactly what I need.

            – Sigur
            24 mins ago











          • Do you think is it possible to change the text also if there is argument? I mean, to print counters are 5,6,7,8 for example.

            – Sigur
            23 mins ago











          • @Sigur Your wish is my command. Updated.

            – egreg
            17 mins ago











          • Oh, I think I should learn about NewDocumentCommand as soon as possible. Amazing and powerful.

            – Sigur
            12 mins ago
















          3














          With expl3 it's just a few lines.



          documentclass{report}
          
usepackage{xparse}
          

          
newcounter{mycount}
          
setcounter{mycount}{0}
          

          
ExplSyntaxOn
          
NewDocumentCommand{foo}{O{1}}
          
 {
          
  int_compare:nT { #1 > 0 }
          
   {
          
    int_compare:nTF { #1 = 1 } {counter~is} {counters~are}~
          
    stepcounter{mycount}
          
    textbf{themycount}
          
    prg_replicate:nn { #1 - 1 } {,stepcounter{mycount}textbf{themycount}}
          
   }
          
 }
          
ExplSyntaxOff
          

          
begin{document}
          
first use: foo
          

          
second use: foo
          

          
now using with option to iterate: foo[2]
          

          
now using with option to iterate: counters are textbf{3,4}
          

          
foo[5]
          

          
end{document}


          The trick is to do the first iteration and then proceed again adding first a comma.



          If the number passed is zero or less nothing happens.



          enter image description here






          share|improve this answer


























          • Exactly what I need.

            – Sigur
            24 mins ago











          • Do you think is it possible to change the text also if there is argument? I mean, to print counters are 5,6,7,8 for example.

            – Sigur
            23 mins ago











          • @Sigur Your wish is my command. Updated.

            – egreg
            17 mins ago











          • Oh, I think I should learn about NewDocumentCommand as soon as possible. Amazing and powerful.

            – Sigur
            12 mins ago














          3












          3








          3







          With expl3 it's just a few lines.



          documentclass{report}
          
usepackage{xparse}
          

          
newcounter{mycount}
          
setcounter{mycount}{0}
          

          
ExplSyntaxOn
          
NewDocumentCommand{foo}{O{1}}
          
 {
          
  int_compare:nT { #1 > 0 }
          
   {
          
    int_compare:nTF { #1 = 1 } {counter~is} {counters~are}~
          
    stepcounter{mycount}
          
    textbf{themycount}
          
    prg_replicate:nn { #1 - 1 } {,stepcounter{mycount}textbf{themycount}}
          
   }
          
 }
          
ExplSyntaxOff
          

          
begin{document}
          
first use: foo
          

          
second use: foo
          

          
now using with option to iterate: foo[2]
          

          
now using with option to iterate: counters are textbf{3,4}
          

          
foo[5]
          

          
end{document}


          The trick is to do the first iteration and then proceed again adding first a comma.



          If the number passed is zero or less nothing happens.



          enter image description here






          share|improve this answer















          With expl3 it's just a few lines.



          documentclass{report}
          
usepackage{xparse}
          

          
newcounter{mycount}
          
setcounter{mycount}{0}
          

          
ExplSyntaxOn
          
NewDocumentCommand{foo}{O{1}}
          
 {
          
  int_compare:nT { #1 > 0 }
          
   {
          
    int_compare:nTF { #1 = 1 } {counter~is} {counters~are}~
          
    stepcounter{mycount}
          
    textbf{themycount}
          
    prg_replicate:nn { #1 - 1 } {,stepcounter{mycount}textbf{themycount}}
          
   }
          
 }
          
ExplSyntaxOff
          

          
begin{document}
          
first use: foo
          

          
second use: foo
          

          
now using with option to iterate: foo[2]
          

          
now using with option to iterate: counters are textbf{3,4}
          

          
foo[5]
          

          
end{document}


          The trick is to do the first iteration and then proceed again adding first a comma.



          If the number passed is zero or less nothing happens.



          enter image description here







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 17 mins ago

























          answered 26 mins ago









          egregegreg

          713k8618943182




          713k8618943182













          • Exactly what I need.

            – Sigur
            24 mins ago











          • Do you think is it possible to change the text also if there is argument? I mean, to print counters are 5,6,7,8 for example.

            – Sigur
            23 mins ago











          • @Sigur Your wish is my command. Updated.

            – egreg
            17 mins ago











          • Oh, I think I should learn about NewDocumentCommand as soon as possible. Amazing and powerful.

            – Sigur
            12 mins ago



















          • Exactly what I need.

            – Sigur
            24 mins ago











          • Do you think is it possible to change the text also if there is argument? I mean, to print counters are 5,6,7,8 for example.

            – Sigur
            23 mins ago











          • @Sigur Your wish is my command. Updated.

            – egreg
            17 mins ago











          • Oh, I think I should learn about NewDocumentCommand as soon as possible. Amazing and powerful.

            – Sigur
            12 mins ago

















          Exactly what I need.

          – Sigur
          24 mins ago





          Exactly what I need.

          – Sigur
          24 mins ago













          Do you think is it possible to change the text also if there is argument? I mean, to print counters are 5,6,7,8 for example.

          – Sigur
          23 mins ago





          Do you think is it possible to change the text also if there is argument? I mean, to print counters are 5,6,7,8 for example.

          – Sigur
          23 mins ago













          @Sigur Your wish is my command. Updated.

          – egreg
          17 mins ago





          @Sigur Your wish is my command. Updated.

          – egreg
          17 mins ago













          Oh, I think I should learn about NewDocumentCommand as soon as possible. Amazing and powerful.

          – Sigur
          12 mins ago





          Oh, I think I should learn about NewDocumentCommand as soon as possible. Amazing and powerful.

          – Sigur
          12 mins ago











          1














          Here is an approach using multido for looping and a delayed delimiter definition:



          enter image description here



          documentclass{article}
          

          
usepackage{multido}
          

          
newcounter{mycount}
          

          
newcommand{foo}[1][1]{%
          
  counter%
          
  ifnum#1>1relax s areelse space isfi
          
  space
          
  % https://tex.stackexchange.com/a/89187/5764
          
  defitemdelim{unskipspacedefitemdelim{,space}}% Item delimiter delayed by one cycle
          
  {bfseriesmultido{i=1+1}{#1}{itemdelim stepcounter{mycount}themycount}}%
          
}
          

          
begin{document}
          

          
first use: foo
          

          
second use: foo
          

          
now using with option to iterate: foo[2]
          

          
medskip
          

          
textit{desired output from line above should be:}
          

          
medskip
          

          
now using with option to iterate: counters are textbf{3, 4}
          

          
end{document}





          share|improve this answer
























          • This solution is more understandable to me... but I had never done it by myself. Very nice.

            – Sigur
            9 mins ago
















          1














          Here is an approach using multido for looping and a delayed delimiter definition:



          enter image description here



          documentclass{article}
          

          
usepackage{multido}
          

          
newcounter{mycount}
          

          
newcommand{foo}[1][1]{%
          
  counter%
          
  ifnum#1>1relax s areelse space isfi
          
  space
          
  % https://tex.stackexchange.com/a/89187/5764
          
  defitemdelim{unskipspacedefitemdelim{,space}}% Item delimiter delayed by one cycle
          
  {bfseriesmultido{i=1+1}{#1}{itemdelim stepcounter{mycount}themycount}}%
          
}
          

          
begin{document}
          

          
first use: foo
          

          
second use: foo
          

          
now using with option to iterate: foo[2]
          

          
medskip
          

          
textit{desired output from line above should be:}
          

          
medskip
          

          
now using with option to iterate: counters are textbf{3, 4}
          

          
end{document}





          share|improve this answer
























          • This solution is more understandable to me... but I had never done it by myself. Very nice.

            – Sigur
            9 mins ago














          1












          1








          1







          Here is an approach using multido for looping and a delayed delimiter definition:



          enter image description here



          documentclass{article}
          

          
usepackage{multido}
          

          
newcounter{mycount}
          

          
newcommand{foo}[1][1]{%
          
  counter%
          
  ifnum#1>1relax s areelse space isfi
          
  space
          
  % https://tex.stackexchange.com/a/89187/5764
          
  defitemdelim{unskipspacedefitemdelim{,space}}% Item delimiter delayed by one cycle
          
  {bfseriesmultido{i=1+1}{#1}{itemdelim stepcounter{mycount}themycount}}%
          
}
          

          
begin{document}
          

          
first use: foo
          

          
second use: foo
          

          
now using with option to iterate: foo[2]
          

          
medskip
          

          
textit{desired output from line above should be:}
          

          
medskip
          

          
now using with option to iterate: counters are textbf{3, 4}
          

          
end{document}





          share|improve this answer













          Here is an approach using multido for looping and a delayed delimiter definition:



          enter image description here



          documentclass{article}
          

          
usepackage{multido}
          

          
newcounter{mycount}
          

          
newcommand{foo}[1][1]{%
          
  counter%
          
  ifnum#1>1relax s areelse space isfi
          
  space
          
  % https://tex.stackexchange.com/a/89187/5764
          
  defitemdelim{unskipspacedefitemdelim{,space}}% Item delimiter delayed by one cycle
          
  {bfseriesmultido{i=1+1}{#1}{itemdelim stepcounter{mycount}themycount}}%
          
}
          

          
begin{document}
          

          
first use: foo
          

          
second use: foo
          

          
now using with option to iterate: foo[2]
          

          
medskip
          

          
textit{desired output from line above should be:}
          

          
medskip
          

          
now using with option to iterate: counters are textbf{3, 4}
          

          
end{document}






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 17 mins ago









          WernerWerner

          440k669681662




          440k669681662













          • This solution is more understandable to me... but I had never done it by myself. Very nice.

            – Sigur
            9 mins ago



















          • This solution is more understandable to me... but I had never done it by myself. Very nice.

            – Sigur
            9 mins ago

















          This solution is more understandable to me... but I had never done it by myself. Very nice.

          – Sigur
          9 mins ago





          This solution is more understandable to me... but I had never done it by myself. Very nice.

          – Sigur
          9 mins ago


















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