How does TikZ render an arc?
With the sample MWE below, TikZ generates the following diagram:
1. Drawing an arc
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}
coordinate[label=below:$a$] (a) at (0,0);
draw (a) arc(0:180:2);
end{tikzpicture}
end{document}
2. Drawing a circle
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}
coordinate[label=below:$a$] (a) at (0,0);
coordinate[label=below:$b$] (b) at (5,5);
draw (a) arc(0:180:2);
draw (b) circle [radius=2cm];
end{tikzpicture}
end{document}
With draw <coordinate> circle
command, TikZ draws a circle, with the <coordinate>
at its center.
With draw <coordinate> arc
command, TikZ draws an arc, with the <coordinate>
as one of its endpoints.
I wish to understand, why this difference of behavior and how is TikZ drawing the arc with draw (a) arc(0:180:2);
.
Why does TikZ does not use (a)
as its center point while drawing an arc similar to drawing a circle.
How does TikZ actually draw the arc with point a
.
What is the reference and center point, when TikZ draws an arc.
tikz-pgf
|
show 6 more comments
With the sample MWE below, TikZ generates the following diagram:
1. Drawing an arc
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}
coordinate[label=below:$a$] (a) at (0,0);
draw (a) arc(0:180:2);
end{tikzpicture}
end{document}
2. Drawing a circle
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}
coordinate[label=below:$a$] (a) at (0,0);
coordinate[label=below:$b$] (b) at (5,5);
draw (a) arc(0:180:2);
draw (b) circle [radius=2cm];
end{tikzpicture}
end{document}
With draw <coordinate> circle
command, TikZ draws a circle, with the <coordinate>
at its center.
With draw <coordinate> arc
command, TikZ draws an arc, with the <coordinate>
as one of its endpoints.
I wish to understand, why this difference of behavior and how is TikZ drawing the arc with draw (a) arc(0:180:2);
.
Why does TikZ does not use (a)
as its center point while drawing an arc similar to drawing a circle.
How does TikZ actually draw the arc with point a
.
What is the reference and center point, when TikZ draws an arc.
tikz-pgf
May I draw your attention to this question? IMHO the question "Why does TikZ does not use(a)
as its center point while drawing an arc similar to drawing a circle?" is not really answerable, and there are more than enough answers that show you how you can get whatever behavior you want.
– marmot
1 hour ago
1
The mathematical geometry of an arc and a circle? Judging from the question you seem to understand it very well. (Internally TikZ approximates them with Bezier curves, if that's your question.)
– marmot
1 hour ago
1
What is the geometry here? It is just simply the beginning angle and the ending angle.
– JouleV
1 hour ago
1
The logic is very simple: considerdraw (x,y) arc(alpha:beta:r);
Now draw a circle of radiusr
such that(x,y)
is at the position specified by the anglealpha
, Now TikZ draws an arc from that point to the point with anglebeta
along that circle.
– marmot
1 hour ago
1
@marmot Yes, but I have to "update" myself right now
– JouleV
1 hour ago
|
show 6 more comments
With the sample MWE below, TikZ generates the following diagram:
1. Drawing an arc
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}
coordinate[label=below:$a$] (a) at (0,0);
draw (a) arc(0:180:2);
end{tikzpicture}
end{document}
2. Drawing a circle
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}
coordinate[label=below:$a$] (a) at (0,0);
coordinate[label=below:$b$] (b) at (5,5);
draw (a) arc(0:180:2);
draw (b) circle [radius=2cm];
end{tikzpicture}
end{document}
With draw <coordinate> circle
command, TikZ draws a circle, with the <coordinate>
at its center.
With draw <coordinate> arc
command, TikZ draws an arc, with the <coordinate>
as one of its endpoints.
I wish to understand, why this difference of behavior and how is TikZ drawing the arc with draw (a) arc(0:180:2);
.
Why does TikZ does not use (a)
as its center point while drawing an arc similar to drawing a circle.
How does TikZ actually draw the arc with point a
.
What is the reference and center point, when TikZ draws an arc.
tikz-pgf
With the sample MWE below, TikZ generates the following diagram:
1. Drawing an arc
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}
coordinate[label=below:$a$] (a) at (0,0);
draw (a) arc(0:180:2);
end{tikzpicture}
end{document}
2. Drawing a circle
documentclass{article}
usepackage{tikz}
begin{document}
begin{tikzpicture}
coordinate[label=below:$a$] (a) at (0,0);
coordinate[label=below:$b$] (b) at (5,5);
draw (a) arc(0:180:2);
draw (b) circle [radius=2cm];
end{tikzpicture}
end{document}
With draw <coordinate> circle
command, TikZ draws a circle, with the <coordinate>
at its center.
With draw <coordinate> arc
command, TikZ draws an arc, with the <coordinate>
as one of its endpoints.
I wish to understand, why this difference of behavior and how is TikZ drawing the arc with draw (a) arc(0:180:2);
.
Why does TikZ does not use (a)
as its center point while drawing an arc similar to drawing a circle.
How does TikZ actually draw the arc with point a
.
What is the reference and center point, when TikZ draws an arc.
tikz-pgf
tikz-pgf
asked 1 hour ago
subham sonisubham soni
5,05483189
5,05483189
May I draw your attention to this question? IMHO the question "Why does TikZ does not use(a)
as its center point while drawing an arc similar to drawing a circle?" is not really answerable, and there are more than enough answers that show you how you can get whatever behavior you want.
– marmot
1 hour ago
1
The mathematical geometry of an arc and a circle? Judging from the question you seem to understand it very well. (Internally TikZ approximates them with Bezier curves, if that's your question.)
– marmot
1 hour ago
1
What is the geometry here? It is just simply the beginning angle and the ending angle.
– JouleV
1 hour ago
1
The logic is very simple: considerdraw (x,y) arc(alpha:beta:r);
Now draw a circle of radiusr
such that(x,y)
is at the position specified by the anglealpha
, Now TikZ draws an arc from that point to the point with anglebeta
along that circle.
– marmot
1 hour ago
1
@marmot Yes, but I have to "update" myself right now
– JouleV
1 hour ago
|
show 6 more comments
May I draw your attention to this question? IMHO the question "Why does TikZ does not use(a)
as its center point while drawing an arc similar to drawing a circle?" is not really answerable, and there are more than enough answers that show you how you can get whatever behavior you want.
– marmot
1 hour ago
1
The mathematical geometry of an arc and a circle? Judging from the question you seem to understand it very well. (Internally TikZ approximates them with Bezier curves, if that's your question.)
– marmot
1 hour ago
1
What is the geometry here? It is just simply the beginning angle and the ending angle.
– JouleV
1 hour ago
1
The logic is very simple: considerdraw (x,y) arc(alpha:beta:r);
Now draw a circle of radiusr
such that(x,y)
is at the position specified by the anglealpha
, Now TikZ draws an arc from that point to the point with anglebeta
along that circle.
– marmot
1 hour ago
1
@marmot Yes, but I have to "update" myself right now
– JouleV
1 hour ago
May I draw your attention to this question? IMHO the question "Why does TikZ does not use
(a)
as its center point while drawing an arc similar to drawing a circle?" is not really answerable, and there are more than enough answers that show you how you can get whatever behavior you want.– marmot
1 hour ago
May I draw your attention to this question? IMHO the question "Why does TikZ does not use
(a)
as its center point while drawing an arc similar to drawing a circle?" is not really answerable, and there are more than enough answers that show you how you can get whatever behavior you want.– marmot
1 hour ago
1
1
The mathematical geometry of an arc and a circle? Judging from the question you seem to understand it very well. (Internally TikZ approximates them with Bezier curves, if that's your question.)
– marmot
1 hour ago
The mathematical geometry of an arc and a circle? Judging from the question you seem to understand it very well. (Internally TikZ approximates them with Bezier curves, if that's your question.)
– marmot
1 hour ago
1
1
What is the geometry here? It is just simply the beginning angle and the ending angle.
– JouleV
1 hour ago
What is the geometry here? It is just simply the beginning angle and the ending angle.
– JouleV
1 hour ago
1
1
The logic is very simple: consider
draw (x,y) arc(alpha:beta:r);
Now draw a circle of radius r
such that (x,y)
is at the position specified by the angle alpha
, Now TikZ draws an arc from that point to the point with angle beta
along that circle.– marmot
1 hour ago
The logic is very simple: consider
draw (x,y) arc(alpha:beta:r);
Now draw a circle of radius r
such that (x,y)
is at the position specified by the angle alpha
, Now TikZ draws an arc from that point to the point with angle beta
along that circle.– marmot
1 hour ago
1
1
@marmot Yes, but I have to "update" myself right now
– JouleV
1 hour ago
@marmot Yes, but I have to "update" myself right now
– JouleV
1 hour ago
|
show 6 more comments
2 Answers
2
active
oldest
votes
Here is an attempt to use attempt to explain step by step what's going on. I use the non-deprecated syntax, as suggested by Joule V.
documentclass{beamer}
usepackage{tikz}
usetikzlibrary{overlay-beamer-styles}
begin{document}
begin{frame}[t]
frametitle{The arc construction}
textbackslashtexttt{draw (P) arc[start angle=$alpha$,end
angle=$beta$,radius=$r$];}
centering
begin{tikzpicture}
node[circle,fill,inner sep=1pt,label=right:{$P=(x,y)$}] (P){};
draw[dashed,visible on=<2-4>] (P) ++ (210:2) coordinate (O) circle[radius=2cm];
draw[visible on=<2>] (O) + (1,0) arc[start angle=00,end angle=30,radius=1cm]
node[midway,right] {$alpha$};
draw[visible on=<2>] (P) -- (O) -- ++(2,0) node[midway,below]{$r$};
draw[visible on=<3>,thick] (P) arc[start angle=30,end angle=135,radius=2cm]
coordinate (Q);
draw[visible on=<3>] (O) + (1,0) arc[start angle=00,end angle=135,radius=1cm]
node[midway,below] {$beta$} (Q) -- (O) -- ++(2,0) ;
path (O) -- ++ (0,2.5); % only for the bounding box
end{tikzpicture}
begin{itemize}
item<+-> Consider a point $P=(x,y)$.
item<+-> Imagine now a circle of radius $r$ for which $P$ sits at the angle
$alpha$.
item<+-> The arc runs along this circle between the angles $alpha$ and
$beta$;
end{itemize}
end{frame}
end{document}
+1, very clear!
– CarLaTeX
40 mins ago
add a comment |
Short answer: arc
has nothing to do with circle
. circle
is drawn with four curves, arc
is drawn with one curve, that is all.
Let's start with tikz.code.tex
. In lines 3673–3706, there is the definition of tikz@do@arc
, based on pgfpatharc
, which is defined in pgfcorepathconstruct.code.tex
. Circles and ellipses are defined in the same way.
In pgfcorepathconstruct.code.tex
, pgfpatharc
is defined as a curve with a starting point and an ending point, based on pgf@nlt@curveto
(line 401).
Meanwhile, you can see that any kind of curves, even circles, are defined based on pgf@nlt@curveto
. Circles and ellipses is defined in pgfpathellipse
as a set of four connected curves: line 926, line 947, line 968, and line 989 — each of these curves has its own pgf@nlt@curveto
.
That is why the arc
does not take its coordinate as the center, but a starting point.
add a comment |
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2 Answers
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2 Answers
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active
oldest
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oldest
votes
Here is an attempt to use attempt to explain step by step what's going on. I use the non-deprecated syntax, as suggested by Joule V.
documentclass{beamer}
usepackage{tikz}
usetikzlibrary{overlay-beamer-styles}
begin{document}
begin{frame}[t]
frametitle{The arc construction}
textbackslashtexttt{draw (P) arc[start angle=$alpha$,end
angle=$beta$,radius=$r$];}
centering
begin{tikzpicture}
node[circle,fill,inner sep=1pt,label=right:{$P=(x,y)$}] (P){};
draw[dashed,visible on=<2-4>] (P) ++ (210:2) coordinate (O) circle[radius=2cm];
draw[visible on=<2>] (O) + (1,0) arc[start angle=00,end angle=30,radius=1cm]
node[midway,right] {$alpha$};
draw[visible on=<2>] (P) -- (O) -- ++(2,0) node[midway,below]{$r$};
draw[visible on=<3>,thick] (P) arc[start angle=30,end angle=135,radius=2cm]
coordinate (Q);
draw[visible on=<3>] (O) + (1,0) arc[start angle=00,end angle=135,radius=1cm]
node[midway,below] {$beta$} (Q) -- (O) -- ++(2,0) ;
path (O) -- ++ (0,2.5); % only for the bounding box
end{tikzpicture}
begin{itemize}
item<+-> Consider a point $P=(x,y)$.
item<+-> Imagine now a circle of radius $r$ for which $P$ sits at the angle
$alpha$.
item<+-> The arc runs along this circle between the angles $alpha$ and
$beta$;
end{itemize}
end{frame}
end{document}
+1, very clear!
– CarLaTeX
40 mins ago
add a comment |
Here is an attempt to use attempt to explain step by step what's going on. I use the non-deprecated syntax, as suggested by Joule V.
documentclass{beamer}
usepackage{tikz}
usetikzlibrary{overlay-beamer-styles}
begin{document}
begin{frame}[t]
frametitle{The arc construction}
textbackslashtexttt{draw (P) arc[start angle=$alpha$,end
angle=$beta$,radius=$r$];}
centering
begin{tikzpicture}
node[circle,fill,inner sep=1pt,label=right:{$P=(x,y)$}] (P){};
draw[dashed,visible on=<2-4>] (P) ++ (210:2) coordinate (O) circle[radius=2cm];
draw[visible on=<2>] (O) + (1,0) arc[start angle=00,end angle=30,radius=1cm]
node[midway,right] {$alpha$};
draw[visible on=<2>] (P) -- (O) -- ++(2,0) node[midway,below]{$r$};
draw[visible on=<3>,thick] (P) arc[start angle=30,end angle=135,radius=2cm]
coordinate (Q);
draw[visible on=<3>] (O) + (1,0) arc[start angle=00,end angle=135,radius=1cm]
node[midway,below] {$beta$} (Q) -- (O) -- ++(2,0) ;
path (O) -- ++ (0,2.5); % only for the bounding box
end{tikzpicture}
begin{itemize}
item<+-> Consider a point $P=(x,y)$.
item<+-> Imagine now a circle of radius $r$ for which $P$ sits at the angle
$alpha$.
item<+-> The arc runs along this circle between the angles $alpha$ and
$beta$;
end{itemize}
end{frame}
end{document}
+1, very clear!
– CarLaTeX
40 mins ago
add a comment |
Here is an attempt to use attempt to explain step by step what's going on. I use the non-deprecated syntax, as suggested by Joule V.
documentclass{beamer}
usepackage{tikz}
usetikzlibrary{overlay-beamer-styles}
begin{document}
begin{frame}[t]
frametitle{The arc construction}
textbackslashtexttt{draw (P) arc[start angle=$alpha$,end
angle=$beta$,radius=$r$];}
centering
begin{tikzpicture}
node[circle,fill,inner sep=1pt,label=right:{$P=(x,y)$}] (P){};
draw[dashed,visible on=<2-4>] (P) ++ (210:2) coordinate (O) circle[radius=2cm];
draw[visible on=<2>] (O) + (1,0) arc[start angle=00,end angle=30,radius=1cm]
node[midway,right] {$alpha$};
draw[visible on=<2>] (P) -- (O) -- ++(2,0) node[midway,below]{$r$};
draw[visible on=<3>,thick] (P) arc[start angle=30,end angle=135,radius=2cm]
coordinate (Q);
draw[visible on=<3>] (O) + (1,0) arc[start angle=00,end angle=135,radius=1cm]
node[midway,below] {$beta$} (Q) -- (O) -- ++(2,0) ;
path (O) -- ++ (0,2.5); % only for the bounding box
end{tikzpicture}
begin{itemize}
item<+-> Consider a point $P=(x,y)$.
item<+-> Imagine now a circle of radius $r$ for which $P$ sits at the angle
$alpha$.
item<+-> The arc runs along this circle between the angles $alpha$ and
$beta$;
end{itemize}
end{frame}
end{document}
Here is an attempt to use attempt to explain step by step what's going on. I use the non-deprecated syntax, as suggested by Joule V.
documentclass{beamer}
usepackage{tikz}
usetikzlibrary{overlay-beamer-styles}
begin{document}
begin{frame}[t]
frametitle{The arc construction}
textbackslashtexttt{draw (P) arc[start angle=$alpha$,end
angle=$beta$,radius=$r$];}
centering
begin{tikzpicture}
node[circle,fill,inner sep=1pt,label=right:{$P=(x,y)$}] (P){};
draw[dashed,visible on=<2-4>] (P) ++ (210:2) coordinate (O) circle[radius=2cm];
draw[visible on=<2>] (O) + (1,0) arc[start angle=00,end angle=30,radius=1cm]
node[midway,right] {$alpha$};
draw[visible on=<2>] (P) -- (O) -- ++(2,0) node[midway,below]{$r$};
draw[visible on=<3>,thick] (P) arc[start angle=30,end angle=135,radius=2cm]
coordinate (Q);
draw[visible on=<3>] (O) + (1,0) arc[start angle=00,end angle=135,radius=1cm]
node[midway,below] {$beta$} (Q) -- (O) -- ++(2,0) ;
path (O) -- ++ (0,2.5); % only for the bounding box
end{tikzpicture}
begin{itemize}
item<+-> Consider a point $P=(x,y)$.
item<+-> Imagine now a circle of radius $r$ for which $P$ sits at the angle
$alpha$.
item<+-> The arc runs along this circle between the angles $alpha$ and
$beta$;
end{itemize}
end{frame}
end{document}
edited 39 mins ago
answered 42 mins ago
marmotmarmot
120k6154290
120k6154290
+1, very clear!
– CarLaTeX
40 mins ago
add a comment |
+1, very clear!
– CarLaTeX
40 mins ago
+1, very clear!
– CarLaTeX
40 mins ago
+1, very clear!
– CarLaTeX
40 mins ago
add a comment |
Short answer: arc
has nothing to do with circle
. circle
is drawn with four curves, arc
is drawn with one curve, that is all.
Let's start with tikz.code.tex
. In lines 3673–3706, there is the definition of tikz@do@arc
, based on pgfpatharc
, which is defined in pgfcorepathconstruct.code.tex
. Circles and ellipses are defined in the same way.
In pgfcorepathconstruct.code.tex
, pgfpatharc
is defined as a curve with a starting point and an ending point, based on pgf@nlt@curveto
(line 401).
Meanwhile, you can see that any kind of curves, even circles, are defined based on pgf@nlt@curveto
. Circles and ellipses is defined in pgfpathellipse
as a set of four connected curves: line 926, line 947, line 968, and line 989 — each of these curves has its own pgf@nlt@curveto
.
That is why the arc
does not take its coordinate as the center, but a starting point.
add a comment |
Short answer: arc
has nothing to do with circle
. circle
is drawn with four curves, arc
is drawn with one curve, that is all.
Let's start with tikz.code.tex
. In lines 3673–3706, there is the definition of tikz@do@arc
, based on pgfpatharc
, which is defined in pgfcorepathconstruct.code.tex
. Circles and ellipses are defined in the same way.
In pgfcorepathconstruct.code.tex
, pgfpatharc
is defined as a curve with a starting point and an ending point, based on pgf@nlt@curveto
(line 401).
Meanwhile, you can see that any kind of curves, even circles, are defined based on pgf@nlt@curveto
. Circles and ellipses is defined in pgfpathellipse
as a set of four connected curves: line 926, line 947, line 968, and line 989 — each of these curves has its own pgf@nlt@curveto
.
That is why the arc
does not take its coordinate as the center, but a starting point.
add a comment |
Short answer: arc
has nothing to do with circle
. circle
is drawn with four curves, arc
is drawn with one curve, that is all.
Let's start with tikz.code.tex
. In lines 3673–3706, there is the definition of tikz@do@arc
, based on pgfpatharc
, which is defined in pgfcorepathconstruct.code.tex
. Circles and ellipses are defined in the same way.
In pgfcorepathconstruct.code.tex
, pgfpatharc
is defined as a curve with a starting point and an ending point, based on pgf@nlt@curveto
(line 401).
Meanwhile, you can see that any kind of curves, even circles, are defined based on pgf@nlt@curveto
. Circles and ellipses is defined in pgfpathellipse
as a set of four connected curves: line 926, line 947, line 968, and line 989 — each of these curves has its own pgf@nlt@curveto
.
That is why the arc
does not take its coordinate as the center, but a starting point.
Short answer: arc
has nothing to do with circle
. circle
is drawn with four curves, arc
is drawn with one curve, that is all.
Let's start with tikz.code.tex
. In lines 3673–3706, there is the definition of tikz@do@arc
, based on pgfpatharc
, which is defined in pgfcorepathconstruct.code.tex
. Circles and ellipses are defined in the same way.
In pgfcorepathconstruct.code.tex
, pgfpatharc
is defined as a curve with a starting point and an ending point, based on pgf@nlt@curveto
(line 401).
Meanwhile, you can see that any kind of curves, even circles, are defined based on pgf@nlt@curveto
. Circles and ellipses is defined in pgfpathellipse
as a set of four connected curves: line 926, line 947, line 968, and line 989 — each of these curves has its own pgf@nlt@curveto
.
That is why the arc
does not take its coordinate as the center, but a starting point.
answered 11 mins ago
JouleVJouleV
14.6k22665
14.6k22665
add a comment |
add a comment |
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May I draw your attention to this question? IMHO the question "Why does TikZ does not use
(a)
as its center point while drawing an arc similar to drawing a circle?" is not really answerable, and there are more than enough answers that show you how you can get whatever behavior you want.– marmot
1 hour ago
1
The mathematical geometry of an arc and a circle? Judging from the question you seem to understand it very well. (Internally TikZ approximates them with Bezier curves, if that's your question.)
– marmot
1 hour ago
1
What is the geometry here? It is just simply the beginning angle and the ending angle.
– JouleV
1 hour ago
1
The logic is very simple: consider
draw (x,y) arc(alpha:beta:r);
Now draw a circle of radiusr
such that(x,y)
is at the position specified by the anglealpha
, Now TikZ draws an arc from that point to the point with anglebeta
along that circle.– marmot
1 hour ago
1
@marmot Yes, but I have to "update" myself right now
– JouleV
1 hour ago