If I score a critical hit on an 18 or higher, what are my chances of getting a critical hit if I roll 3d20?
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I have Elven Accuracy so with advantage on an attack roll using Dexterity, Intelligence, Wisdom, or Charisma, you can reroll one of the dice once.
So what are my crit chance with a crit range of 18/20 with three rolls also what would be the crit chance with a crit range of 17/20 with three rolls.
dnd-5e statistics critical-hit
New contributor
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add a comment |
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I have Elven Accuracy so with advantage on an attack roll using Dexterity, Intelligence, Wisdom, or Charisma, you can reroll one of the dice once.
So what are my crit chance with a crit range of 18/20 with three rolls also what would be the crit chance with a crit range of 17/20 with three rolls.
dnd-5e statistics critical-hit
New contributor
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2
$begingroup$
The notation you're using for the crit range is unusual. Are you describing a Champion Fighter? If so, where are you getting the 17/20 range from?
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– Xirema
14 hours ago
1
$begingroup$
What class/sub class is your character?
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– KorvinStarmast
14 hours ago
4
$begingroup$
Possible duplicate of What are my chances of rolling a natural 19/20 critical if I roll 3d20?
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– Julien Lopez
12 hours ago
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Welcome to RPG.SE! Take the tour if you haven't already, and check out the help center for more guidance.
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– V2Blast
2 hours ago
add a comment |
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I have Elven Accuracy so with advantage on an attack roll using Dexterity, Intelligence, Wisdom, or Charisma, you can reroll one of the dice once.
So what are my crit chance with a crit range of 18/20 with three rolls also what would be the crit chance with a crit range of 17/20 with three rolls.
dnd-5e statistics critical-hit
New contributor
$endgroup$
I have Elven Accuracy so with advantage on an attack roll using Dexterity, Intelligence, Wisdom, or Charisma, you can reroll one of the dice once.
So what are my crit chance with a crit range of 18/20 with three rolls also what would be the crit chance with a crit range of 17/20 with three rolls.
dnd-5e statistics critical-hit
dnd-5e statistics critical-hit
New contributor
New contributor
edited 14 hours ago
divibisan
1,738620
1,738620
New contributor
asked 15 hours ago
Braymal GamingBraymal Gaming
613
613
New contributor
New contributor
2
$begingroup$
The notation you're using for the crit range is unusual. Are you describing a Champion Fighter? If so, where are you getting the 17/20 range from?
$endgroup$
– Xirema
14 hours ago
1
$begingroup$
What class/sub class is your character?
$endgroup$
– KorvinStarmast
14 hours ago
4
$begingroup$
Possible duplicate of What are my chances of rolling a natural 19/20 critical if I roll 3d20?
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– Julien Lopez
12 hours ago
$begingroup$
Welcome to RPG.SE! Take the tour if you haven't already, and check out the help center for more guidance.
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– V2Blast
2 hours ago
add a comment |
2
$begingroup$
The notation you're using for the crit range is unusual. Are you describing a Champion Fighter? If so, where are you getting the 17/20 range from?
$endgroup$
– Xirema
14 hours ago
1
$begingroup$
What class/sub class is your character?
$endgroup$
– KorvinStarmast
14 hours ago
4
$begingroup$
Possible duplicate of What are my chances of rolling a natural 19/20 critical if I roll 3d20?
$endgroup$
– Julien Lopez
12 hours ago
$begingroup$
Welcome to RPG.SE! Take the tour if you haven't already, and check out the help center for more guidance.
$endgroup$
– V2Blast
2 hours ago
2
2
$begingroup$
The notation you're using for the crit range is unusual. Are you describing a Champion Fighter? If so, where are you getting the 17/20 range from?
$endgroup$
– Xirema
14 hours ago
$begingroup$
The notation you're using for the crit range is unusual. Are you describing a Champion Fighter? If so, where are you getting the 17/20 range from?
$endgroup$
– Xirema
14 hours ago
1
1
$begingroup$
What class/sub class is your character?
$endgroup$
– KorvinStarmast
14 hours ago
$begingroup$
What class/sub class is your character?
$endgroup$
– KorvinStarmast
14 hours ago
4
4
$begingroup$
Possible duplicate of What are my chances of rolling a natural 19/20 critical if I roll 3d20?
$endgroup$
– Julien Lopez
12 hours ago
$begingroup$
Possible duplicate of What are my chances of rolling a natural 19/20 critical if I roll 3d20?
$endgroup$
– Julien Lopez
12 hours ago
$begingroup$
Welcome to RPG.SE! Take the tour if you haven't already, and check out the help center for more guidance.
$endgroup$
– V2Blast
2 hours ago
$begingroup$
Welcome to RPG.SE! Take the tour if you haven't already, and check out the help center for more guidance.
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– V2Blast
2 hours ago
add a comment |
4 Answers
4
active
oldest
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$begingroup$
For "at least one" probability problems, it's usually easier to start by calculating the chance that none of the dice crit, as that saves you the hassle of combining the probabilities of getting 1/2/3 crits.
Best of three rolls with 18-20 crit range: ~39% chance to crit
Chance that a single die will not crit: 17/20 = 0.85
Chance that all three dice will not crit: (17/20) x (17/20) x (17/20) = 0.614125
Chance that at least one die will crit: 1 - (17/20)3 = 0.385875
Best of three rolls with 17-20 crit range: ~49% chance to crit
Chance that a single die will not crit: 16/20 = 0.8
Chance that all three dice will not crit: (16/20) x (16/20) x (16/20) = 0.512
Chance that at least one die will crit: 1 - (16/20)3 = 0.488
$endgroup$
3
$begingroup$
This is excellent advice. Probability of success is 100% - probability of failure. Many times calculating failure is way easier than calculating success.
$endgroup$
– Nelson
4 hours ago
add a comment |
$begingroup$
The other answers do a good job of answering the question, but I'll point out how you can answer questions like this in the future:
https://anydice.com/ is a very powerful (if slightly complicated) calculator for these sorts of questions. In your case, you'd enter the query:
output [highest 1 of 3d20]
And then select "At Least" from options below to get this table, which shows the odds of getting at least each number:
The result, is 38.59% for a crit range of 18, and 48.8% for a crit range of 17
$endgroup$
add a comment |
$begingroup$
If p is the probability of a crit on a single role, then 1-(1-p)^N is the probability of at least one crit on N roles.
so for N=3 and p=3/20, P=38.6%
for crit range 17-20, P=48.8% (WOW!)
$endgroup$
$begingroup$
so noted. I have now edited my answer
$endgroup$
– Jeremy
14 hours ago
add a comment |
$begingroup$
It depends on how you use the Elven Accuracy Die
There's two ways that players are legally allowed to use the Elven Accuracy Die:
- Replace the lower of the two advantage dice (Type A)
- Replace the higher of the two advantage dice (Type B)
In the former case, this roll is mathematically equivalent to rolling 3 dice and taking the highest. In the latter case, it's more like rolling two dice, taking the lower, and then taking the higher of that result and a third die.
begin{array}{r|l|l}
text{Outcomes} & text{18-20 A} & text{18-20 B}
\ hline
text{Non-Crit} & text{61.413%} & text{83.088%} \
text{Crit} & text{38.588%} & text{16.913%} \
end{array}
begin{array}{r|l|l}
& text{17-20 A} & text{17-20 B} \ hline
text{Non-Crit} & text{51.200%} & text{76.800%} \
text{Crit} & text{48.800%} & text{23.200%} \
end{array}
Note: as far as I'm aware, in 5th Edition D&D, it is not possible to get a Critical hit range that includes 17. It's possible I'm unaware of a specific class feature or magic item that is expanding the range beyond what can be attained by a Champion Fighter at level 15. But as a result, the second table (the 17-20 range) does not have practical use in this game.
$endgroup$
1
$begingroup$
That seems a bit convoluted since the rerolling is optional but I suppose it doesn't hurt to have the extra data.
$endgroup$
– Sdjz
14 hours ago
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
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$begingroup$
For "at least one" probability problems, it's usually easier to start by calculating the chance that none of the dice crit, as that saves you the hassle of combining the probabilities of getting 1/2/3 crits.
Best of three rolls with 18-20 crit range: ~39% chance to crit
Chance that a single die will not crit: 17/20 = 0.85
Chance that all three dice will not crit: (17/20) x (17/20) x (17/20) = 0.614125
Chance that at least one die will crit: 1 - (17/20)3 = 0.385875
Best of three rolls with 17-20 crit range: ~49% chance to crit
Chance that a single die will not crit: 16/20 = 0.8
Chance that all three dice will not crit: (16/20) x (16/20) x (16/20) = 0.512
Chance that at least one die will crit: 1 - (16/20)3 = 0.488
$endgroup$
3
$begingroup$
This is excellent advice. Probability of success is 100% - probability of failure. Many times calculating failure is way easier than calculating success.
$endgroup$
– Nelson
4 hours ago
add a comment |
$begingroup$
For "at least one" probability problems, it's usually easier to start by calculating the chance that none of the dice crit, as that saves you the hassle of combining the probabilities of getting 1/2/3 crits.
Best of three rolls with 18-20 crit range: ~39% chance to crit
Chance that a single die will not crit: 17/20 = 0.85
Chance that all three dice will not crit: (17/20) x (17/20) x (17/20) = 0.614125
Chance that at least one die will crit: 1 - (17/20)3 = 0.385875
Best of three rolls with 17-20 crit range: ~49% chance to crit
Chance that a single die will not crit: 16/20 = 0.8
Chance that all three dice will not crit: (16/20) x (16/20) x (16/20) = 0.512
Chance that at least one die will crit: 1 - (16/20)3 = 0.488
$endgroup$
3
$begingroup$
This is excellent advice. Probability of success is 100% - probability of failure. Many times calculating failure is way easier than calculating success.
$endgroup$
– Nelson
4 hours ago
add a comment |
$begingroup$
For "at least one" probability problems, it's usually easier to start by calculating the chance that none of the dice crit, as that saves you the hassle of combining the probabilities of getting 1/2/3 crits.
Best of three rolls with 18-20 crit range: ~39% chance to crit
Chance that a single die will not crit: 17/20 = 0.85
Chance that all three dice will not crit: (17/20) x (17/20) x (17/20) = 0.614125
Chance that at least one die will crit: 1 - (17/20)3 = 0.385875
Best of three rolls with 17-20 crit range: ~49% chance to crit
Chance that a single die will not crit: 16/20 = 0.8
Chance that all three dice will not crit: (16/20) x (16/20) x (16/20) = 0.512
Chance that at least one die will crit: 1 - (16/20)3 = 0.488
$endgroup$
For "at least one" probability problems, it's usually easier to start by calculating the chance that none of the dice crit, as that saves you the hassle of combining the probabilities of getting 1/2/3 crits.
Best of three rolls with 18-20 crit range: ~39% chance to crit
Chance that a single die will not crit: 17/20 = 0.85
Chance that all three dice will not crit: (17/20) x (17/20) x (17/20) = 0.614125
Chance that at least one die will crit: 1 - (17/20)3 = 0.385875
Best of three rolls with 17-20 crit range: ~49% chance to crit
Chance that a single die will not crit: 16/20 = 0.8
Chance that all three dice will not crit: (16/20) x (16/20) x (16/20) = 0.512
Chance that at least one die will crit: 1 - (16/20)3 = 0.488
edited 11 hours ago
answered 14 hours ago
Oblivious SageOblivious Sage
43.5k14137199
43.5k14137199
3
$begingroup$
This is excellent advice. Probability of success is 100% - probability of failure. Many times calculating failure is way easier than calculating success.
$endgroup$
– Nelson
4 hours ago
add a comment |
3
$begingroup$
This is excellent advice. Probability of success is 100% - probability of failure. Many times calculating failure is way easier than calculating success.
$endgroup$
– Nelson
4 hours ago
3
3
$begingroup$
This is excellent advice. Probability of success is 100% - probability of failure. Many times calculating failure is way easier than calculating success.
$endgroup$
– Nelson
4 hours ago
$begingroup$
This is excellent advice. Probability of success is 100% - probability of failure. Many times calculating failure is way easier than calculating success.
$endgroup$
– Nelson
4 hours ago
add a comment |
$begingroup$
The other answers do a good job of answering the question, but I'll point out how you can answer questions like this in the future:
https://anydice.com/ is a very powerful (if slightly complicated) calculator for these sorts of questions. In your case, you'd enter the query:
output [highest 1 of 3d20]
And then select "At Least" from options below to get this table, which shows the odds of getting at least each number:
The result, is 38.59% for a crit range of 18, and 48.8% for a crit range of 17
$endgroup$
add a comment |
$begingroup$
The other answers do a good job of answering the question, but I'll point out how you can answer questions like this in the future:
https://anydice.com/ is a very powerful (if slightly complicated) calculator for these sorts of questions. In your case, you'd enter the query:
output [highest 1 of 3d20]
And then select "At Least" from options below to get this table, which shows the odds of getting at least each number:
The result, is 38.59% for a crit range of 18, and 48.8% for a crit range of 17
$endgroup$
add a comment |
$begingroup$
The other answers do a good job of answering the question, but I'll point out how you can answer questions like this in the future:
https://anydice.com/ is a very powerful (if slightly complicated) calculator for these sorts of questions. In your case, you'd enter the query:
output [highest 1 of 3d20]
And then select "At Least" from options below to get this table, which shows the odds of getting at least each number:
The result, is 38.59% for a crit range of 18, and 48.8% for a crit range of 17
$endgroup$
The other answers do a good job of answering the question, but I'll point out how you can answer questions like this in the future:
https://anydice.com/ is a very powerful (if slightly complicated) calculator for these sorts of questions. In your case, you'd enter the query:
output [highest 1 of 3d20]
And then select "At Least" from options below to get this table, which shows the odds of getting at least each number:
The result, is 38.59% for a crit range of 18, and 48.8% for a crit range of 17
edited 14 hours ago
Sdjz
14.1k467114
14.1k467114
answered 14 hours ago
divibisandivibisan
1,738620
1,738620
add a comment |
add a comment |
$begingroup$
If p is the probability of a crit on a single role, then 1-(1-p)^N is the probability of at least one crit on N roles.
so for N=3 and p=3/20, P=38.6%
for crit range 17-20, P=48.8% (WOW!)
$endgroup$
$begingroup$
so noted. I have now edited my answer
$endgroup$
– Jeremy
14 hours ago
add a comment |
$begingroup$
If p is the probability of a crit on a single role, then 1-(1-p)^N is the probability of at least one crit on N roles.
so for N=3 and p=3/20, P=38.6%
for crit range 17-20, P=48.8% (WOW!)
$endgroup$
$begingroup$
so noted. I have now edited my answer
$endgroup$
– Jeremy
14 hours ago
add a comment |
$begingroup$
If p is the probability of a crit on a single role, then 1-(1-p)^N is the probability of at least one crit on N roles.
so for N=3 and p=3/20, P=38.6%
for crit range 17-20, P=48.8% (WOW!)
$endgroup$
If p is the probability of a crit on a single role, then 1-(1-p)^N is the probability of at least one crit on N roles.
so for N=3 and p=3/20, P=38.6%
for crit range 17-20, P=48.8% (WOW!)
edited 14 hours ago
answered 14 hours ago
JeremyJeremy
1865
1865
$begingroup$
so noted. I have now edited my answer
$endgroup$
– Jeremy
14 hours ago
add a comment |
$begingroup$
so noted. I have now edited my answer
$endgroup$
– Jeremy
14 hours ago
$begingroup$
so noted. I have now edited my answer
$endgroup$
– Jeremy
14 hours ago
$begingroup$
so noted. I have now edited my answer
$endgroup$
– Jeremy
14 hours ago
add a comment |
$begingroup$
It depends on how you use the Elven Accuracy Die
There's two ways that players are legally allowed to use the Elven Accuracy Die:
- Replace the lower of the two advantage dice (Type A)
- Replace the higher of the two advantage dice (Type B)
In the former case, this roll is mathematically equivalent to rolling 3 dice and taking the highest. In the latter case, it's more like rolling two dice, taking the lower, and then taking the higher of that result and a third die.
begin{array}{r|l|l}
text{Outcomes} & text{18-20 A} & text{18-20 B}
\ hline
text{Non-Crit} & text{61.413%} & text{83.088%} \
text{Crit} & text{38.588%} & text{16.913%} \
end{array}
begin{array}{r|l|l}
& text{17-20 A} & text{17-20 B} \ hline
text{Non-Crit} & text{51.200%} & text{76.800%} \
text{Crit} & text{48.800%} & text{23.200%} \
end{array}
Note: as far as I'm aware, in 5th Edition D&D, it is not possible to get a Critical hit range that includes 17. It's possible I'm unaware of a specific class feature or magic item that is expanding the range beyond what can be attained by a Champion Fighter at level 15. But as a result, the second table (the 17-20 range) does not have practical use in this game.
$endgroup$
1
$begingroup$
That seems a bit convoluted since the rerolling is optional but I suppose it doesn't hurt to have the extra data.
$endgroup$
– Sdjz
14 hours ago
add a comment |
$begingroup$
It depends on how you use the Elven Accuracy Die
There's two ways that players are legally allowed to use the Elven Accuracy Die:
- Replace the lower of the two advantage dice (Type A)
- Replace the higher of the two advantage dice (Type B)
In the former case, this roll is mathematically equivalent to rolling 3 dice and taking the highest. In the latter case, it's more like rolling two dice, taking the lower, and then taking the higher of that result and a third die.
begin{array}{r|l|l}
text{Outcomes} & text{18-20 A} & text{18-20 B}
\ hline
text{Non-Crit} & text{61.413%} & text{83.088%} \
text{Crit} & text{38.588%} & text{16.913%} \
end{array}
begin{array}{r|l|l}
& text{17-20 A} & text{17-20 B} \ hline
text{Non-Crit} & text{51.200%} & text{76.800%} \
text{Crit} & text{48.800%} & text{23.200%} \
end{array}
Note: as far as I'm aware, in 5th Edition D&D, it is not possible to get a Critical hit range that includes 17. It's possible I'm unaware of a specific class feature or magic item that is expanding the range beyond what can be attained by a Champion Fighter at level 15. But as a result, the second table (the 17-20 range) does not have practical use in this game.
$endgroup$
1
$begingroup$
That seems a bit convoluted since the rerolling is optional but I suppose it doesn't hurt to have the extra data.
$endgroup$
– Sdjz
14 hours ago
add a comment |
$begingroup$
It depends on how you use the Elven Accuracy Die
There's two ways that players are legally allowed to use the Elven Accuracy Die:
- Replace the lower of the two advantage dice (Type A)
- Replace the higher of the two advantage dice (Type B)
In the former case, this roll is mathematically equivalent to rolling 3 dice and taking the highest. In the latter case, it's more like rolling two dice, taking the lower, and then taking the higher of that result and a third die.
begin{array}{r|l|l}
text{Outcomes} & text{18-20 A} & text{18-20 B}
\ hline
text{Non-Crit} & text{61.413%} & text{83.088%} \
text{Crit} & text{38.588%} & text{16.913%} \
end{array}
begin{array}{r|l|l}
& text{17-20 A} & text{17-20 B} \ hline
text{Non-Crit} & text{51.200%} & text{76.800%} \
text{Crit} & text{48.800%} & text{23.200%} \
end{array}
Note: as far as I'm aware, in 5th Edition D&D, it is not possible to get a Critical hit range that includes 17. It's possible I'm unaware of a specific class feature or magic item that is expanding the range beyond what can be attained by a Champion Fighter at level 15. But as a result, the second table (the 17-20 range) does not have practical use in this game.
$endgroup$
It depends on how you use the Elven Accuracy Die
There's two ways that players are legally allowed to use the Elven Accuracy Die:
- Replace the lower of the two advantage dice (Type A)
- Replace the higher of the two advantage dice (Type B)
In the former case, this roll is mathematically equivalent to rolling 3 dice and taking the highest. In the latter case, it's more like rolling two dice, taking the lower, and then taking the higher of that result and a third die.
begin{array}{r|l|l}
text{Outcomes} & text{18-20 A} & text{18-20 B}
\ hline
text{Non-Crit} & text{61.413%} & text{83.088%} \
text{Crit} & text{38.588%} & text{16.913%} \
end{array}
begin{array}{r|l|l}
& text{17-20 A} & text{17-20 B} \ hline
text{Non-Crit} & text{51.200%} & text{76.800%} \
text{Crit} & text{48.800%} & text{23.200%} \
end{array}
Note: as far as I'm aware, in 5th Edition D&D, it is not possible to get a Critical hit range that includes 17. It's possible I'm unaware of a specific class feature or magic item that is expanding the range beyond what can be attained by a Champion Fighter at level 15. But as a result, the second table (the 17-20 range) does not have practical use in this game.
answered 14 hours ago
XiremaXirema
23.8k268140
23.8k268140
1
$begingroup$
That seems a bit convoluted since the rerolling is optional but I suppose it doesn't hurt to have the extra data.
$endgroup$
– Sdjz
14 hours ago
add a comment |
1
$begingroup$
That seems a bit convoluted since the rerolling is optional but I suppose it doesn't hurt to have the extra data.
$endgroup$
– Sdjz
14 hours ago
1
1
$begingroup$
That seems a bit convoluted since the rerolling is optional but I suppose it doesn't hurt to have the extra data.
$endgroup$
– Sdjz
14 hours ago
$begingroup$
That seems a bit convoluted since the rerolling is optional but I suppose it doesn't hurt to have the extra data.
$endgroup$
– Sdjz
14 hours ago
add a comment |
Braymal Gaming is a new contributor. Be nice, and check out our Code of Conduct.
Braymal Gaming is a new contributor. Be nice, and check out our Code of Conduct.
Braymal Gaming is a new contributor. Be nice, and check out our Code of Conduct.
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2
$begingroup$
The notation you're using for the crit range is unusual. Are you describing a Champion Fighter? If so, where are you getting the 17/20 range from?
$endgroup$
– Xirema
14 hours ago
1
$begingroup$
What class/sub class is your character?
$endgroup$
– KorvinStarmast
14 hours ago
4
$begingroup$
Possible duplicate of What are my chances of rolling a natural 19/20 critical if I roll 3d20?
$endgroup$
– Julien Lopez
12 hours ago
$begingroup$
Welcome to RPG.SE! Take the tour if you haven't already, and check out the help center for more guidance.
$endgroup$
– V2Blast
2 hours ago