Which big number is bigger?












2












$begingroup$


Input



Integers a1, a2, a3, b1, b2, b3 each in the range 1 to 20.



Output



True if a1^(a2^a3) > b1^(b2^b3) and False otherwise.


^ is exponentiation in this question.



Rules



This is code-golf. Your code must terminate correctly within 10 seconds for any valid input on a standard desktop PC.



You can output anything Truthy for True and anything Falsey for False.



Test cases



3^(4^5) > 5^(4^3)

1^(2^3) < 3^(2^1)

3^(6^5) < 5^(20^3)

20^(20^20) > 20^(20^19)

20^(20^20) is not bigger than 20^(20^20)





code-golf







share|improve this question











$endgroup$








  • 1




    $begingroup$
    It would probably also benefit from normal, broadly-defined decision-problem output instead of being restricted to 1 and 0
    $endgroup$
    – Unrelated String
    21 mins ago






  • 1




    $begingroup$
    Can we take the inputs in any order?
    $endgroup$
    – Kevin Cruijssen
    20 mins ago










  • $begingroup$
    @KevinCruijssen No. They have to be in the order given.
    $endgroup$
    – Anush
    17 mins ago






  • 1




    $begingroup$
    Suggested test case to make sure that all solutions can support high values: 20^(20^20) > 19^(20^20).
    $endgroup$
    – Arnauld
    5 mins ago










  • $begingroup$
    Suggested test case: where a1,a2,a3 are equal to b1,b2,b3, which should result in falsey.
    $endgroup$
    – Kevin Cruijssen
    4 mins ago


















2












$begingroup$


Input



Integers a1, a2, a3, b1, b2, b3 each in the range 1 to 20.



Output



True if a1^(a2^a3) > b1^(b2^b3) and False otherwise.


^ is exponentiation in this question.



Rules



This is code-golf. Your code must terminate correctly within 10 seconds for any valid input on a standard desktop PC.



You can output anything Truthy for True and anything Falsey for False.



Test cases



3^(4^5) > 5^(4^3)

1^(2^3) < 3^(2^1)

3^(6^5) < 5^(20^3)

20^(20^20) > 20^(20^19)

20^(20^20) is not bigger than 20^(20^20)





code-golf







share|improve this question











$endgroup$








  • 1




    $begingroup$
    It would probably also benefit from normal, broadly-defined decision-problem output instead of being restricted to 1 and 0
    $endgroup$
    – Unrelated String
    21 mins ago






  • 1




    $begingroup$
    Can we take the inputs in any order?
    $endgroup$
    – Kevin Cruijssen
    20 mins ago










  • $begingroup$
    @KevinCruijssen No. They have to be in the order given.
    $endgroup$
    – Anush
    17 mins ago






  • 1




    $begingroup$
    Suggested test case to make sure that all solutions can support high values: 20^(20^20) > 19^(20^20).
    $endgroup$
    – Arnauld
    5 mins ago










  • $begingroup$
    Suggested test case: where a1,a2,a3 are equal to b1,b2,b3, which should result in falsey.
    $endgroup$
    – Kevin Cruijssen
    4 mins ago
















2












2








2





$begingroup$


Input



Integers a1, a2, a3, b1, b2, b3 each in the range 1 to 20.



Output



True if a1^(a2^a3) > b1^(b2^b3) and False otherwise.


^ is exponentiation in this question.



Rules



This is code-golf. Your code must terminate correctly within 10 seconds for any valid input on a standard desktop PC.



You can output anything Truthy for True and anything Falsey for False.



Test cases



3^(4^5) > 5^(4^3)

1^(2^3) < 3^(2^1)

3^(6^5) < 5^(20^3)

20^(20^20) > 20^(20^19)

20^(20^20) is not bigger than 20^(20^20)





code-golf







share|improve this question











$endgroup$




Input



Integers a1, a2, a3, b1, b2, b3 each in the range 1 to 20.



Output



True if a1^(a2^a3) > b1^(b2^b3) and False otherwise.


^ is exponentiation in this question.



Rules



This is code-golf. Your code must terminate correctly within 10 seconds for any valid input on a standard desktop PC.



You can output anything Truthy for True and anything Falsey for False.



Test cases



3^(4^5) > 5^(4^3)

1^(2^3) < 3^(2^1)

3^(6^5) < 5^(20^3)

20^(20^20) > 20^(20^19)

20^(20^20) is not bigger than 20^(20^20)





code-golf




code-golf






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 51 secs ago







Anush

















asked 24 mins ago









AnushAnush

849627




849627








  • 1




    $begingroup$
    It would probably also benefit from normal, broadly-defined decision-problem output instead of being restricted to 1 and 0
    $endgroup$
    – Unrelated String
    21 mins ago






  • 1




    $begingroup$
    Can we take the inputs in any order?
    $endgroup$
    – Kevin Cruijssen
    20 mins ago










  • $begingroup$
    @KevinCruijssen No. They have to be in the order given.
    $endgroup$
    – Anush
    17 mins ago






  • 1




    $begingroup$
    Suggested test case to make sure that all solutions can support high values: 20^(20^20) > 19^(20^20).
    $endgroup$
    – Arnauld
    5 mins ago










  • $begingroup$
    Suggested test case: where a1,a2,a3 are equal to b1,b2,b3, which should result in falsey.
    $endgroup$
    – Kevin Cruijssen
    4 mins ago
















  • 1




    $begingroup$
    It would probably also benefit from normal, broadly-defined decision-problem output instead of being restricted to 1 and 0
    $endgroup$
    – Unrelated String
    21 mins ago






  • 1




    $begingroup$
    Can we take the inputs in any order?
    $endgroup$
    – Kevin Cruijssen
    20 mins ago










  • $begingroup$
    @KevinCruijssen No. They have to be in the order given.
    $endgroup$
    – Anush
    17 mins ago






  • 1




    $begingroup$
    Suggested test case to make sure that all solutions can support high values: 20^(20^20) > 19^(20^20).
    $endgroup$
    – Arnauld
    5 mins ago










  • $begingroup$
    Suggested test case: where a1,a2,a3 are equal to b1,b2,b3, which should result in falsey.
    $endgroup$
    – Kevin Cruijssen
    4 mins ago










1




1




$begingroup$
It would probably also benefit from normal, broadly-defined decision-problem output instead of being restricted to 1 and 0
$endgroup$
– Unrelated String
21 mins ago




$begingroup$
It would probably also benefit from normal, broadly-defined decision-problem output instead of being restricted to 1 and 0
$endgroup$
– Unrelated String
21 mins ago




1




1




$begingroup$
Can we take the inputs in any order?
$endgroup$
– Kevin Cruijssen
20 mins ago




$begingroup$
Can we take the inputs in any order?
$endgroup$
– Kevin Cruijssen
20 mins ago












$begingroup$
@KevinCruijssen No. They have to be in the order given.
$endgroup$
– Anush
17 mins ago




$begingroup$
@KevinCruijssen No. They have to be in the order given.
$endgroup$
– Anush
17 mins ago




1




1




$begingroup$
Suggested test case to make sure that all solutions can support high values: 20^(20^20) > 19^(20^20).
$endgroup$
– Arnauld
5 mins ago




$begingroup$
Suggested test case to make sure that all solutions can support high values: 20^(20^20) > 19^(20^20).
$endgroup$
– Arnauld
5 mins ago












$begingroup$
Suggested test case: where a1,a2,a3 are equal to b1,b2,b3, which should result in falsey.
$endgroup$
– Kevin Cruijssen
4 mins ago






$begingroup$
Suggested test case: where a1,a2,a3 are equal to b1,b2,b3, which should result in falsey.
$endgroup$
– Kevin Cruijssen
4 mins ago












5 Answers
5






active

oldest

votes


















5












$begingroup$

JavaScript (ES6), 43 bytes



Returns $true$ if $a^{b^c} > d^{e^f}$, or $false$ otherwise.





(a,b,c,d,e,f)=>b*c*(l=Math.log)(a)>e*f*l(d)


Try it online!






share|improve this answer









$endgroup$













  • $begingroup$
    Eheh we had the same idea... and almost the same byte count :P
    $endgroup$
    – digEmAll
    11 mins ago



















3












$begingroup$


R, 42 bytes





function(a,b,c,d,e,f)log(a)*b*c>log(d)*e*f


Try it online!






share|improve this answer









$endgroup$





















    1












    $begingroup$


    Perl 6, 25 bytes





    * **(* ** *)>* **(* ** *)


    Try it online!





    share









    $endgroup$













    • $begingroup$
      This doesn't work if all the variables are set to 20.
      $endgroup$
      – Anush
      5 mins ago










    • $begingroup$
      (20,20,20,20,20,20) results in a number overflow error
      $endgroup$
      – Kevin Cruijssen
      5 mins ago



















    0












    $begingroup$


    05AB1E, 11 bytes



    Uses the method from Arnauld's JS answer



    .²**U.²**X‹


    Try it online!



    2F.²**ˆ}¯`› also works at the same byte count






    share|improve this answer











    $endgroup$













    • $begingroup$
      This doesn't terminate for a1=20, a2=20, a3=20.
      $endgroup$
      – Anush
      15 mins ago






    • 1




      $begingroup$
      @Anush: Seems to terminate in less than a second to me.
      $endgroup$
      – Emigna
      13 mins ago










    • $begingroup$
      you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
      $endgroup$
      – Anush
      13 mins ago










    • $begingroup$
      @Anush: Ah, you meant b1=b2=b3=20 ,yeah that doesn't terminate.
      $endgroup$
      – Emigna
      12 mins ago










    • $begingroup$
      Yes, sorry. That is what I meant.
      $endgroup$
      – Anush
      23 secs ago



















    0












    $begingroup$


    05AB1E, 11 bytes



    2F.²**ˆ}¯`›


    Input as six separated inputs.



    Try it online.



    Or alternatively:



    εεN_i.²]P`›


    Input as [[a1,a2,a3],[b1,b2,b3]].



    Try it online.





    share









    $endgroup$














      Your Answer






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      5 Answers
      5






      active

      oldest

      votes








      5 Answers
      5






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      5












      $begingroup$

      JavaScript (ES6), 43 bytes



      Returns $true$ if $a^{b^c} > d^{e^f}$, or $false$ otherwise.





      (a,b,c,d,e,f)=>b*c*(l=Math.log)(a)>e*f*l(d)


      Try it online!






      share|improve this answer









      $endgroup$













      • $begingroup$
        Eheh we had the same idea... and almost the same byte count :P
        $endgroup$
        – digEmAll
        11 mins ago
















      5












      $begingroup$

      JavaScript (ES6), 43 bytes



      Returns $true$ if $a^{b^c} > d^{e^f}$, or $false$ otherwise.





      (a,b,c,d,e,f)=>b*c*(l=Math.log)(a)>e*f*l(d)


      Try it online!






      share|improve this answer









      $endgroup$













      • $begingroup$
        Eheh we had the same idea... and almost the same byte count :P
        $endgroup$
        – digEmAll
        11 mins ago














      5












      5








      5





      $begingroup$

      JavaScript (ES6), 43 bytes



      Returns $true$ if $a^{b^c} > d^{e^f}$, or $false$ otherwise.





      (a,b,c,d,e,f)=>b*c*(l=Math.log)(a)>e*f*l(d)


      Try it online!






      share|improve this answer









      $endgroup$



      JavaScript (ES6), 43 bytes



      Returns $true$ if $a^{b^c} > d^{e^f}$, or $false$ otherwise.





      (a,b,c,d,e,f)=>b*c*(l=Math.log)(a)>e*f*l(d)


      Try it online!







      share|improve this answer












      share|improve this answer



      share|improve this answer










      answered 15 mins ago









      ArnauldArnauld

      82.1k798337




      82.1k798337












      • $begingroup$
        Eheh we had the same idea... and almost the same byte count :P
        $endgroup$
        – digEmAll
        11 mins ago


















      • $begingroup$
        Eheh we had the same idea... and almost the same byte count :P
        $endgroup$
        – digEmAll
        11 mins ago
















      $begingroup$
      Eheh we had the same idea... and almost the same byte count :P
      $endgroup$
      – digEmAll
      11 mins ago




      $begingroup$
      Eheh we had the same idea... and almost the same byte count :P
      $endgroup$
      – digEmAll
      11 mins ago











      3












      $begingroup$


      R, 42 bytes





      function(a,b,c,d,e,f)log(a)*b*c>log(d)*e*f


      Try it online!






      share|improve this answer









      $endgroup$


















        3












        $begingroup$


        R, 42 bytes





        function(a,b,c,d,e,f)log(a)*b*c>log(d)*e*f


        Try it online!






        share|improve this answer









        $endgroup$
















          3












          3








          3





          $begingroup$


          R, 42 bytes





          function(a,b,c,d,e,f)log(a)*b*c>log(d)*e*f


          Try it online!






          share|improve this answer









          $endgroup$




          R, 42 bytes





          function(a,b,c,d,e,f)log(a)*b*c>log(d)*e*f


          Try it online!







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 12 mins ago









          digEmAlldigEmAll

          3,654515




          3,654515























              1












              $begingroup$


              Perl 6, 25 bytes





              * **(* ** *)>* **(* ** *)


              Try it online!





              share









              $endgroup$













              • $begingroup$
                This doesn't work if all the variables are set to 20.
                $endgroup$
                – Anush
                5 mins ago










              • $begingroup$
                (20,20,20,20,20,20) results in a number overflow error
                $endgroup$
                – Kevin Cruijssen
                5 mins ago
















              1












              $begingroup$


              Perl 6, 25 bytes





              * **(* ** *)>* **(* ** *)


              Try it online!





              share









              $endgroup$













              • $begingroup$
                This doesn't work if all the variables are set to 20.
                $endgroup$
                – Anush
                5 mins ago










              • $begingroup$
                (20,20,20,20,20,20) results in a number overflow error
                $endgroup$
                – Kevin Cruijssen
                5 mins ago














              1












              1








              1





              $begingroup$


              Perl 6, 25 bytes





              * **(* ** *)>* **(* ** *)


              Try it online!





              share









              $endgroup$




              Perl 6, 25 bytes





              * **(* ** *)>* **(* ** *)


              Try it online!






              share











              share


              share










              answered 7 mins ago









              Phil HPhil H

              1,176817




              1,176817












              • $begingroup$
                This doesn't work if all the variables are set to 20.
                $endgroup$
                – Anush
                5 mins ago










              • $begingroup$
                (20,20,20,20,20,20) results in a number overflow error
                $endgroup$
                – Kevin Cruijssen
                5 mins ago


















              • $begingroup$
                This doesn't work if all the variables are set to 20.
                $endgroup$
                – Anush
                5 mins ago










              • $begingroup$
                (20,20,20,20,20,20) results in a number overflow error
                $endgroup$
                – Kevin Cruijssen
                5 mins ago
















              $begingroup$
              This doesn't work if all the variables are set to 20.
              $endgroup$
              – Anush
              5 mins ago




              $begingroup$
              This doesn't work if all the variables are set to 20.
              $endgroup$
              – Anush
              5 mins ago












              $begingroup$
              (20,20,20,20,20,20) results in a number overflow error
              $endgroup$
              – Kevin Cruijssen
              5 mins ago




              $begingroup$
              (20,20,20,20,20,20) results in a number overflow error
              $endgroup$
              – Kevin Cruijssen
              5 mins ago











              0












              $begingroup$


              05AB1E, 11 bytes



              Uses the method from Arnauld's JS answer



              .²**U.²**X‹


              Try it online!



              2F.²**ˆ}¯`› also works at the same byte count






              share|improve this answer











              $endgroup$













              • $begingroup$
                This doesn't terminate for a1=20, a2=20, a3=20.
                $endgroup$
                – Anush
                15 mins ago






              • 1




                $begingroup$
                @Anush: Seems to terminate in less than a second to me.
                $endgroup$
                – Emigna
                13 mins ago










              • $begingroup$
                you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
                $endgroup$
                – Anush
                13 mins ago










              • $begingroup$
                @Anush: Ah, you meant b1=b2=b3=20 ,yeah that doesn't terminate.
                $endgroup$
                – Emigna
                12 mins ago










              • $begingroup$
                Yes, sorry. That is what I meant.
                $endgroup$
                – Anush
                23 secs ago
















              0












              $begingroup$


              05AB1E, 11 bytes



              Uses the method from Arnauld's JS answer



              .²**U.²**X‹


              Try it online!



              2F.²**ˆ}¯`› also works at the same byte count






              share|improve this answer











              $endgroup$













              • $begingroup$
                This doesn't terminate for a1=20, a2=20, a3=20.
                $endgroup$
                – Anush
                15 mins ago






              • 1




                $begingroup$
                @Anush: Seems to terminate in less than a second to me.
                $endgroup$
                – Emigna
                13 mins ago










              • $begingroup$
                you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
                $endgroup$
                – Anush
                13 mins ago










              • $begingroup$
                @Anush: Ah, you meant b1=b2=b3=20 ,yeah that doesn't terminate.
                $endgroup$
                – Emigna
                12 mins ago










              • $begingroup$
                Yes, sorry. That is what I meant.
                $endgroup$
                – Anush
                23 secs ago














              0












              0








              0





              $begingroup$


              05AB1E, 11 bytes



              Uses the method from Arnauld's JS answer



              .²**U.²**X‹


              Try it online!



              2F.²**ˆ}¯`› also works at the same byte count






              share|improve this answer











              $endgroup$




              05AB1E, 11 bytes



              Uses the method from Arnauld's JS answer



              .²**U.²**X‹


              Try it online!



              2F.²**ˆ}¯`› also works at the same byte count







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited 2 mins ago

























              answered 18 mins ago









              EmignaEmigna

              48.3k434147




              48.3k434147












              • $begingroup$
                This doesn't terminate for a1=20, a2=20, a3=20.
                $endgroup$
                – Anush
                15 mins ago






              • 1




                $begingroup$
                @Anush: Seems to terminate in less than a second to me.
                $endgroup$
                – Emigna
                13 mins ago










              • $begingroup$
                you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
                $endgroup$
                – Anush
                13 mins ago










              • $begingroup$
                @Anush: Ah, you meant b1=b2=b3=20 ,yeah that doesn't terminate.
                $endgroup$
                – Emigna
                12 mins ago










              • $begingroup$
                Yes, sorry. That is what I meant.
                $endgroup$
                – Anush
                23 secs ago


















              • $begingroup$
                This doesn't terminate for a1=20, a2=20, a3=20.
                $endgroup$
                – Anush
                15 mins ago






              • 1




                $begingroup$
                @Anush: Seems to terminate in less than a second to me.
                $endgroup$
                – Emigna
                13 mins ago










              • $begingroup$
                you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
                $endgroup$
                – Anush
                13 mins ago










              • $begingroup$
                @Anush: Ah, you meant b1=b2=b3=20 ,yeah that doesn't terminate.
                $endgroup$
                – Emigna
                12 mins ago










              • $begingroup$
                Yes, sorry. That is what I meant.
                $endgroup$
                – Anush
                23 secs ago
















              $begingroup$
              This doesn't terminate for a1=20, a2=20, a3=20.
              $endgroup$
              – Anush
              15 mins ago




              $begingroup$
              This doesn't terminate for a1=20, a2=20, a3=20.
              $endgroup$
              – Anush
              15 mins ago




              1




              1




              $begingroup$
              @Anush: Seems to terminate in less than a second to me.
              $endgroup$
              – Emigna
              13 mins ago




              $begingroup$
              @Anush: Seems to terminate in less than a second to me.
              $endgroup$
              – Emigna
              13 mins ago












              $begingroup$
              you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
              $endgroup$
              – Anush
              13 mins ago




              $begingroup$
              you have to set all the variables to 20. See tio.run/##yy9OTMpM/f9f79Du3GK9Q6tzHzXs@v8/2shAB4xiuRBMAA
              $endgroup$
              – Anush
              13 mins ago












              $begingroup$
              @Anush: Ah, you meant b1=b2=b3=20 ,yeah that doesn't terminate.
              $endgroup$
              – Emigna
              12 mins ago




              $begingroup$
              @Anush: Ah, you meant b1=b2=b3=20 ,yeah that doesn't terminate.
              $endgroup$
              – Emigna
              12 mins ago












              $begingroup$
              Yes, sorry. That is what I meant.
              $endgroup$
              – Anush
              23 secs ago




              $begingroup$
              Yes, sorry. That is what I meant.
              $endgroup$
              – Anush
              23 secs ago











              0












              $begingroup$


              05AB1E, 11 bytes



              2F.²**ˆ}¯`›


              Input as six separated inputs.



              Try it online.



              Or alternatively:



              εεN_i.²]P`›


              Input as [[a1,a2,a3],[b1,b2,b3]].



              Try it online.





              share









              $endgroup$


















                0












                $begingroup$


                05AB1E, 11 bytes



                2F.²**ˆ}¯`›


                Input as six separated inputs.



                Try it online.



                Or alternatively:



                εεN_i.²]P`›


                Input as [[a1,a2,a3],[b1,b2,b3]].



                Try it online.





                share









                $endgroup$
















                  0












                  0








                  0





                  $begingroup$


                  05AB1E, 11 bytes



                  2F.²**ˆ}¯`›


                  Input as six separated inputs.



                  Try it online.



                  Or alternatively:



                  εεN_i.²]P`›


                  Input as [[a1,a2,a3],[b1,b2,b3]].



                  Try it online.





                  share









                  $endgroup$




                  05AB1E, 11 bytes



                  2F.²**ˆ}¯`›


                  Input as six separated inputs.



                  Try it online.



                  Or alternatively:



                  εεN_i.²]P`›


                  Input as [[a1,a2,a3],[b1,b2,b3]].



                  Try it online.






                  share











                  share


                  share










                  answered 28 secs ago









                  Kevin CruijssenKevin Cruijssen

                  43.5k573222




                  43.5k573222






























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