Is there any pythonic way to find average of specific tuple elements in array?





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6















I want to write this code as pythonic. My real array much bigger than this example.



( 5+10+20+3+2 ) / 5




print(np.mean(array,key=lambda x:x[1]))
TypeError: mean() got an unexpected keyword argument 'key'




array = [('a', 5) , ('b', 10), ('c', 20), ('d', 3), ('e', 2)]



sum = 0

for i in range(len(array)):

    sum = sum + array[i][1]



average = sum / len(array)

print(average)



import numpy as np

print(np.mean(array,key=lambda x:x[1]))


How can avoid this?
I want to use second example.






python arrays python-3.x tuples average







share|improve this question

























  • What version of Python are you using?

    – Peter Wood
    2 hours ago






  • 1





    @PeterWood python 3.7

    – Şevval Kahraman
    1 hour ago


















6















I want to write this code as pythonic. My real array much bigger than this example.



( 5+10+20+3+2 ) / 5




print(np.mean(array,key=lambda x:x[1]))
TypeError: mean() got an unexpected keyword argument 'key'




array = [('a', 5) , ('b', 10), ('c', 20), ('d', 3), ('e', 2)]



sum = 0

for i in range(len(array)):

    sum = sum + array[i][1]



average = sum / len(array)

print(average)



import numpy as np

print(np.mean(array,key=lambda x:x[1]))


How can avoid this?
I want to use second example.






python arrays python-3.x tuples average







share|improve this question

























  • What version of Python are you using?

    – Peter Wood
    2 hours ago






  • 1





    @PeterWood python 3.7

    – Şevval Kahraman
    1 hour ago














6












6








6








I want to write this code as pythonic. My real array much bigger than this example.



( 5+10+20+3+2 ) / 5




print(np.mean(array,key=lambda x:x[1]))
TypeError: mean() got an unexpected keyword argument 'key'




array = [('a', 5) , ('b', 10), ('c', 20), ('d', 3), ('e', 2)]



sum = 0

for i in range(len(array)):

    sum = sum + array[i][1]



average = sum / len(array)

print(average)



import numpy as np

print(np.mean(array,key=lambda x:x[1]))


How can avoid this?
I want to use second example.






python arrays python-3.x tuples average







share|improve this question
















I want to write this code as pythonic. My real array much bigger than this example.



( 5+10+20+3+2 ) / 5




print(np.mean(array,key=lambda x:x[1]))
TypeError: mean() got an unexpected keyword argument 'key'




array = [('a', 5) , ('b', 10), ('c', 20), ('d', 3), ('e', 2)]



sum = 0

for i in range(len(array)):

    sum = sum + array[i][1]



average = sum / len(array)

print(average)



import numpy as np

print(np.mean(array,key=lambda x:x[1]))


How can avoid this?
I want to use second example.






python arrays python-3.x tuples average




python arrays python-3.x tuples average






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 41 mins ago









ruohola

1,884420




1,884420










asked 2 hours ago









Şevval KahramanŞevval Kahraman

695




695













  • What version of Python are you using?

    – Peter Wood
    2 hours ago






  • 1





    @PeterWood python 3.7

    – Şevval Kahraman
    1 hour ago



















  • What version of Python are you using?

    – Peter Wood
    2 hours ago






  • 1





    @PeterWood python 3.7

    – Şevval Kahraman
    1 hour ago

















What version of Python are you using?

– Peter Wood
2 hours ago





What version of Python are you using?

– Peter Wood
2 hours ago




1




1





@PeterWood python 3.7

– Şevval Kahraman
1 hour ago





@PeterWood python 3.7

– Şevval Kahraman
1 hour ago












7 Answers
7






active

oldest

votes


















7














If you are using Python 3.4 or above, you could use the statistics module:



from statistics import mean



average = mean(value[1] for value in array)


Or if you're using a version of Python older than 3.4:



average = sum(value[1] for value in array) / len(array)


If you're using Python 2, and you're summing integers, we will have integer division, which will truncate the result, e.g:



>>> 25 / 4

6



>>> 25 / float(4)

6.25


To ensure we don't have integer division we could set the starting value of sum to be the float value 0.0. However, this also means we have to make the loop over the values in the array into a comprehension expression, otherwise it's a syntax error, and it's less pretty, as noted in the comments:



average = sum((value[1] for value in array), 0.0) / len(array)


It's probably best to use fsum from the math module which will return a float:



from math import fsum



average = fsum(value[1] for value in array) / len(array)





share|improve this answer


























  • I realised there are better ways to do the Python 2 code. sum takes an argument for the starting value. If you pass 0.0 to it, then the numerator will always be floating point, nothing to worry about. Also, there is a function in the math module, fsum.

    – Peter Wood
    1 hour ago











  • I would say the float casting way is little bit more self-explanatory than passing a weird 0.0 value argument for the sum.

    – ruohola
    37 mins ago













  • @ruohola I think using fsum is probably best for Python 2.

    – Peter Wood
    24 mins ago



















1














You could use map:



np.mean(list(map(lambda x: x[1], array)))






share|improve this answer
























  • works, thanks a lot

    – Şevval Kahraman
    1 hour ago



















0














With pure Python:



from operator import itemgetter



acc = 0

count = 0



for value in map(itemgetter(1), array):

    acc += value

    count += 1



mean = acc / count


An iterative approach can be preferable if your data cannot fit in memory as a list (since you said it was big). If it can, prefer a declarative approach:



data = [sub[1] for sub in array]

mean = sum(data) / len(data)


If you are open to using numpy, I find this cleaner:



a = np.array(array)



mean = a[:, 1].astype(int).mean()





share|improve this answer

































    0














    Just find the average using sum and number of elements of the list.



    array = [('a', 5) , ('b', 10), ('c', 20), ('d', 3), ('e', 2)]
    
avg = float(sum(value[1] for value in array)) / float(len(array))
    
print(avg)
    
#8.0





    share|improve this answer


























    • Fixed it, Thank you for the suggestion @PeterWood

      – Devesh Kumar Singh
      2 hours ago



















    0














    you can use map instead of list comprehension



    sum(map(lambda x:int(x[1]), array)) / len(array)


    or functools.reduce (if you use Python2.X just reduce not functools.reduce)



    import functools
    
functools.reduce(lambda acc, y: acc + y[1], array, 0) / len(array)





    share|improve this answer


























    • first one gives this error : 'int' object is not callable

      – Şevval Kahraman
      1 hour ago



















    0














    Besides all the nice and cool answers below, there is something in your example code that is not pythonic at all, the for loop with range/len. This can be written, amongst other even more sophisticated ways, like:



    for i in array:
    
    sum = sum + i[1]





    share|improve this answer
























    • This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review

      – manish
      9 mins ago



















    0














    You can simply use:



    print(sum(tup[1] for tup in array) / len(array))


    Or for Python 2:



    print(sum(tup[1] for tup in array) / float(len(array)))


    Or little bit more concisely for Python 2:



    from math import fsum
    

    
print(fsum(tup[1] for tup in array) / len(array))





    share|improve this answer


























    • it gives this error : 'int' object is not callable

      – Şevval Kahraman
      1 hour ago











    • @DeveshKumarSingh just need to cast the len to a float for python2: float(len(array)).

      – ruohola
      54 mins ago











    • @ŞevvalKahraman it gives no errors for me with your example array, you probably have a typo somewhere.

      – ruohola
      53 mins ago













    • @ruohola The reason it works for the example is it's 40 / 5 which gives 8 with no remainder. In Python 2, with different numbers, it could truncate the answer.

      – Peter Wood
      49 mins ago











    • @PeterWood it will not truncate anything if you use the float(len(array)) casting when using Python 2. Anyways it shouldn't even matter since this question was for Python 3.x.

      – ruohola
      44 mins ago














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    7 Answers
    7






    active

    oldest

    votes








    7 Answers
    7






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    7














    If you are using Python 3.4 or above, you could use the statistics module:



    from statistics import mean
    

    
average = mean(value[1] for value in array)


    Or if you're using a version of Python older than 3.4:



    average = sum(value[1] for value in array) / len(array)


    If you're using Python 2, and you're summing integers, we will have integer division, which will truncate the result, e.g:



    >>> 25 / 4
    
6
    

    
>>> 25 / float(4)
    
6.25


    To ensure we don't have integer division we could set the starting value of sum to be the float value 0.0. However, this also means we have to make the loop over the values in the array into a comprehension expression, otherwise it's a syntax error, and it's less pretty, as noted in the comments:



    average = sum((value[1] for value in array), 0.0) / len(array)


    It's probably best to use fsum from the math module which will return a float:



    from math import fsum
    

    
average = fsum(value[1] for value in array) / len(array)





    share|improve this answer


























    • I realised there are better ways to do the Python 2 code. sum takes an argument for the starting value. If you pass 0.0 to it, then the numerator will always be floating point, nothing to worry about. Also, there is a function in the math module, fsum.

      – Peter Wood
      1 hour ago











    • I would say the float casting way is little bit more self-explanatory than passing a weird 0.0 value argument for the sum.

      – ruohola
      37 mins ago













    • @ruohola I think using fsum is probably best for Python 2.

      – Peter Wood
      24 mins ago
















    7














    If you are using Python 3.4 or above, you could use the statistics module:



    from statistics import mean
    

    
average = mean(value[1] for value in array)


    Or if you're using a version of Python older than 3.4:



    average = sum(value[1] for value in array) / len(array)


    If you're using Python 2, and you're summing integers, we will have integer division, which will truncate the result, e.g:



    >>> 25 / 4
    
6
    

    
>>> 25 / float(4)
    
6.25


    To ensure we don't have integer division we could set the starting value of sum to be the float value 0.0. However, this also means we have to make the loop over the values in the array into a comprehension expression, otherwise it's a syntax error, and it's less pretty, as noted in the comments:



    average = sum((value[1] for value in array), 0.0) / len(array)


    It's probably best to use fsum from the math module which will return a float:



    from math import fsum
    

    
average = fsum(value[1] for value in array) / len(array)





    share|improve this answer


























    • I realised there are better ways to do the Python 2 code. sum takes an argument for the starting value. If you pass 0.0 to it, then the numerator will always be floating point, nothing to worry about. Also, there is a function in the math module, fsum.

      – Peter Wood
      1 hour ago











    • I would say the float casting way is little bit more self-explanatory than passing a weird 0.0 value argument for the sum.

      – ruohola
      37 mins ago













    • @ruohola I think using fsum is probably best for Python 2.

      – Peter Wood
      24 mins ago














    7












    7








    7







    If you are using Python 3.4 or above, you could use the statistics module:



    from statistics import mean
    

    
average = mean(value[1] for value in array)


    Or if you're using a version of Python older than 3.4:



    average = sum(value[1] for value in array) / len(array)


    If you're using Python 2, and you're summing integers, we will have integer division, which will truncate the result, e.g:



    >>> 25 / 4
    
6
    

    
>>> 25 / float(4)
    
6.25


    To ensure we don't have integer division we could set the starting value of sum to be the float value 0.0. However, this also means we have to make the loop over the values in the array into a comprehension expression, otherwise it's a syntax error, and it's less pretty, as noted in the comments:



    average = sum((value[1] for value in array), 0.0) / len(array)


    It's probably best to use fsum from the math module which will return a float:



    from math import fsum
    

    
average = fsum(value[1] for value in array) / len(array)





    share|improve this answer















    If you are using Python 3.4 or above, you could use the statistics module:



    from statistics import mean
    

    
average = mean(value[1] for value in array)


    Or if you're using a version of Python older than 3.4:



    average = sum(value[1] for value in array) / len(array)


    If you're using Python 2, and you're summing integers, we will have integer division, which will truncate the result, e.g:



    >>> 25 / 4
    
6
    

    
>>> 25 / float(4)
    
6.25


    To ensure we don't have integer division we could set the starting value of sum to be the float value 0.0. However, this also means we have to make the loop over the values in the array into a comprehension expression, otherwise it's a syntax error, and it's less pretty, as noted in the comments:



    average = sum((value[1] for value in array), 0.0) / len(array)


    It's probably best to use fsum from the math module which will return a float:



    from math import fsum
    

    
average = fsum(value[1] for value in array) / len(array)






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 32 mins ago

























    answered 2 hours ago









    Peter WoodPeter Wood

    16.8k33876




    16.8k33876













    • I realised there are better ways to do the Python 2 code. sum takes an argument for the starting value. If you pass 0.0 to it, then the numerator will always be floating point, nothing to worry about. Also, there is a function in the math module, fsum.

      – Peter Wood
      1 hour ago











    • I would say the float casting way is little bit more self-explanatory than passing a weird 0.0 value argument for the sum.

      – ruohola
      37 mins ago













    • @ruohola I think using fsum is probably best for Python 2.

      – Peter Wood
      24 mins ago



















    • I realised there are better ways to do the Python 2 code. sum takes an argument for the starting value. If you pass 0.0 to it, then the numerator will always be floating point, nothing to worry about. Also, there is a function in the math module, fsum.

      – Peter Wood
      1 hour ago











    • I would say the float casting way is little bit more self-explanatory than passing a weird 0.0 value argument for the sum.

      – ruohola
      37 mins ago













    • @ruohola I think using fsum is probably best for Python 2.

      – Peter Wood
      24 mins ago

















    I realised there are better ways to do the Python 2 code. sum takes an argument for the starting value. If you pass 0.0 to it, then the numerator will always be floating point, nothing to worry about. Also, there is a function in the math module, fsum.

    – Peter Wood
    1 hour ago





    I realised there are better ways to do the Python 2 code. sum takes an argument for the starting value. If you pass 0.0 to it, then the numerator will always be floating point, nothing to worry about. Also, there is a function in the math module, fsum.

    – Peter Wood
    1 hour ago













    I would say the float casting way is little bit more self-explanatory than passing a weird 0.0 value argument for the sum.

    – ruohola
    37 mins ago







    I would say the float casting way is little bit more self-explanatory than passing a weird 0.0 value argument for the sum.

    – ruohola
    37 mins ago















    @ruohola I think using fsum is probably best for Python 2.

    – Peter Wood
    24 mins ago





    @ruohola I think using fsum is probably best for Python 2.

    – Peter Wood
    24 mins ago













    1














    You could use map:



    np.mean(list(map(lambda x: x[1], array)))






    share|improve this answer
























    • works, thanks a lot

      – Şevval Kahraman
      1 hour ago
















    1














    You could use map:



    np.mean(list(map(lambda x: x[1], array)))






    share|improve this answer
























    • works, thanks a lot

      – Şevval Kahraman
      1 hour ago














    1












    1








    1







    You could use map:



    np.mean(list(map(lambda x: x[1], array)))






    share|improve this answer













    You could use map:



    np.mean(list(map(lambda x: x[1], array)))







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered 2 hours ago









    pdpinopdpino

    1667




    1667













    • works, thanks a lot

      – Şevval Kahraman
      1 hour ago



















    • works, thanks a lot

      – Şevval Kahraman
      1 hour ago

















    works, thanks a lot

    – Şevval Kahraman
    1 hour ago





    works, thanks a lot

    – Şevval Kahraman
    1 hour ago











    0














    With pure Python:



    from operator import itemgetter
    

    
acc = 0
    
count = 0
    

    
for value in map(itemgetter(1), array):
    
    acc += value
    
    count += 1
    

    
mean = acc / count


    An iterative approach can be preferable if your data cannot fit in memory as a list (since you said it was big). If it can, prefer a declarative approach:



    data = [sub[1] for sub in array]
    
mean = sum(data) / len(data)


    If you are open to using numpy, I find this cleaner:



    a = np.array(array)
    

    
mean = a[:, 1].astype(int).mean()





    share|improve this answer






























      0














      With pure Python:



      from operator import itemgetter
      

      
acc = 0
      
count = 0
      

      
for value in map(itemgetter(1), array):
      
    acc += value
      
    count += 1
      

      
mean = acc / count


      An iterative approach can be preferable if your data cannot fit in memory as a list (since you said it was big). If it can, prefer a declarative approach:



      data = [sub[1] for sub in array]
      
mean = sum(data) / len(data)


      If you are open to using numpy, I find this cleaner:



      a = np.array(array)
      

      
mean = a[:, 1].astype(int).mean()





      share|improve this answer




























        0












        0








        0







        With pure Python:



        from operator import itemgetter
        

        
acc = 0
        
count = 0
        

        
for value in map(itemgetter(1), array):
        
    acc += value
        
    count += 1
        

        
mean = acc / count


        An iterative approach can be preferable if your data cannot fit in memory as a list (since you said it was big). If it can, prefer a declarative approach:



        data = [sub[1] for sub in array]
        
mean = sum(data) / len(data)


        If you are open to using numpy, I find this cleaner:



        a = np.array(array)
        

        
mean = a[:, 1].astype(int).mean()





        share|improve this answer















        With pure Python:



        from operator import itemgetter
        

        
acc = 0
        
count = 0
        

        
for value in map(itemgetter(1), array):
        
    acc += value
        
    count += 1
        

        
mean = acc / count


        An iterative approach can be preferable if your data cannot fit in memory as a list (since you said it was big). If it can, prefer a declarative approach:



        data = [sub[1] for sub in array]
        
mean = sum(data) / len(data)


        If you are open to using numpy, I find this cleaner:



        a = np.array(array)
        

        
mean = a[:, 1].astype(int).mean()






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 2 hours ago

























        answered 2 hours ago









        gmdsgmds

        8,040932




        8,040932























            0














            Just find the average using sum and number of elements of the list.



            array = [('a', 5) , ('b', 10), ('c', 20), ('d', 3), ('e', 2)]
            
avg = float(sum(value[1] for value in array)) / float(len(array))
            
print(avg)
            
#8.0





            share|improve this answer


























            • Fixed it, Thank you for the suggestion @PeterWood

              – Devesh Kumar Singh
              2 hours ago
















            0














            Just find the average using sum and number of elements of the list.



            array = [('a', 5) , ('b', 10), ('c', 20), ('d', 3), ('e', 2)]
            
avg = float(sum(value[1] for value in array)) / float(len(array))
            
print(avg)
            
#8.0





            share|improve this answer


























            • Fixed it, Thank you for the suggestion @PeterWood

              – Devesh Kumar Singh
              2 hours ago














            0












            0








            0







            Just find the average using sum and number of elements of the list.



            array = [('a', 5) , ('b', 10), ('c', 20), ('d', 3), ('e', 2)]
            
avg = float(sum(value[1] for value in array)) / float(len(array))
            
print(avg)
            
#8.0





            share|improve this answer















            Just find the average using sum and number of elements of the list.



            array = [('a', 5) , ('b', 10), ('c', 20), ('d', 3), ('e', 2)]
            
avg = float(sum(value[1] for value in array)) / float(len(array))
            
print(avg)
            
#8.0






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 2 hours ago

























            answered 2 hours ago









            Devesh Kumar SinghDevesh Kumar Singh

            3,4421425




            3,4421425













            • Fixed it, Thank you for the suggestion @PeterWood

              – Devesh Kumar Singh
              2 hours ago



















            • Fixed it, Thank you for the suggestion @PeterWood

              – Devesh Kumar Singh
              2 hours ago

















            Fixed it, Thank you for the suggestion @PeterWood

            – Devesh Kumar Singh
            2 hours ago





            Fixed it, Thank you for the suggestion @PeterWood

            – Devesh Kumar Singh
            2 hours ago











            0














            you can use map instead of list comprehension



            sum(map(lambda x:int(x[1]), array)) / len(array)


            or functools.reduce (if you use Python2.X just reduce not functools.reduce)



            import functools
            
functools.reduce(lambda acc, y: acc + y[1], array, 0) / len(array)





            share|improve this answer


























            • first one gives this error : 'int' object is not callable

              – Şevval Kahraman
              1 hour ago
















            0














            you can use map instead of list comprehension



            sum(map(lambda x:int(x[1]), array)) / len(array)


            or functools.reduce (if you use Python2.X just reduce not functools.reduce)



            import functools
            
functools.reduce(lambda acc, y: acc + y[1], array, 0) / len(array)





            share|improve this answer


























            • first one gives this error : 'int' object is not callable

              – Şevval Kahraman
              1 hour ago














            0












            0








            0







            you can use map instead of list comprehension



            sum(map(lambda x:int(x[1]), array)) / len(array)


            or functools.reduce (if you use Python2.X just reduce not functools.reduce)



            import functools
            
functools.reduce(lambda acc, y: acc + y[1], array, 0) / len(array)





            share|improve this answer















            you can use map instead of list comprehension



            sum(map(lambda x:int(x[1]), array)) / len(array)


            or functools.reduce (if you use Python2.X just reduce not functools.reduce)



            import functools
            
functools.reduce(lambda acc, y: acc + y[1], array, 0) / len(array)






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 2 hours ago

























            answered 2 hours ago









            minjiminji

            157110




            157110













            • first one gives this error : 'int' object is not callable

              – Şevval Kahraman
              1 hour ago



















            • first one gives this error : 'int' object is not callable

              – Şevval Kahraman
              1 hour ago

















            first one gives this error : 'int' object is not callable

            – Şevval Kahraman
            1 hour ago





            first one gives this error : 'int' object is not callable

            – Şevval Kahraman
            1 hour ago











            0














            Besides all the nice and cool answers below, there is something in your example code that is not pythonic at all, the for loop with range/len. This can be written, amongst other even more sophisticated ways, like:



            for i in array:
            
    sum = sum + i[1]





            share|improve this answer
























            • This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review

              – manish
              9 mins ago
















            0














            Besides all the nice and cool answers below, there is something in your example code that is not pythonic at all, the for loop with range/len. This can be written, amongst other even more sophisticated ways, like:



            for i in array:
            
    sum = sum + i[1]





            share|improve this answer
























            • This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review

              – manish
              9 mins ago














            0












            0








            0







            Besides all the nice and cool answers below, there is something in your example code that is not pythonic at all, the for loop with range/len. This can be written, amongst other even more sophisticated ways, like:



            for i in array:
            
    sum = sum + i[1]





            share|improve this answer













            Besides all the nice and cool answers below, there is something in your example code that is not pythonic at all, the for loop with range/len. This can be written, amongst other even more sophisticated ways, like:



            for i in array:
            
    sum = sum + i[1]






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 30 mins ago









            carnicercarnicer

            1476




            1476













            • This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review

              – manish
              9 mins ago



















            • This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review

              – manish
              9 mins ago

















            This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review

            – manish
            9 mins ago





            This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review

            – manish
            9 mins ago











            0














            You can simply use:



            print(sum(tup[1] for tup in array) / len(array))


            Or for Python 2:



            print(sum(tup[1] for tup in array) / float(len(array)))


            Or little bit more concisely for Python 2:



            from math import fsum
            

            
print(fsum(tup[1] for tup in array) / len(array))





            share|improve this answer


























            • it gives this error : 'int' object is not callable

              – Şevval Kahraman
              1 hour ago











            • @DeveshKumarSingh just need to cast the len to a float for python2: float(len(array)).

              – ruohola
              54 mins ago











            • @ŞevvalKahraman it gives no errors for me with your example array, you probably have a typo somewhere.

              – ruohola
              53 mins ago













            • @ruohola The reason it works for the example is it's 40 / 5 which gives 8 with no remainder. In Python 2, with different numbers, it could truncate the answer.

              – Peter Wood
              49 mins ago











            • @PeterWood it will not truncate anything if you use the float(len(array)) casting when using Python 2. Anyways it shouldn't even matter since this question was for Python 3.x.

              – ruohola
              44 mins ago


















            0














            You can simply use:



            print(sum(tup[1] for tup in array) / len(array))


            Or for Python 2:



            print(sum(tup[1] for tup in array) / float(len(array)))


            Or little bit more concisely for Python 2:



            from math import fsum
            

            
print(fsum(tup[1] for tup in array) / len(array))





            share|improve this answer


























            • it gives this error : 'int' object is not callable

              – Şevval Kahraman
              1 hour ago











            • @DeveshKumarSingh just need to cast the len to a float for python2: float(len(array)).

              – ruohola
              54 mins ago











            • @ŞevvalKahraman it gives no errors for me with your example array, you probably have a typo somewhere.

              – ruohola
              53 mins ago













            • @ruohola The reason it works for the example is it's 40 / 5 which gives 8 with no remainder. In Python 2, with different numbers, it could truncate the answer.

              – Peter Wood
              49 mins ago











            • @PeterWood it will not truncate anything if you use the float(len(array)) casting when using Python 2. Anyways it shouldn't even matter since this question was for Python 3.x.

              – ruohola
              44 mins ago
















            0












            0








            0







            You can simply use:



            print(sum(tup[1] for tup in array) / len(array))


            Or for Python 2:



            print(sum(tup[1] for tup in array) / float(len(array)))


            Or little bit more concisely for Python 2:



            from math import fsum
            

            
print(fsum(tup[1] for tup in array) / len(array))





            share|improve this answer















            You can simply use:



            print(sum(tup[1] for tup in array) / len(array))


            Or for Python 2:



            print(sum(tup[1] for tup in array) / float(len(array)))


            Or little bit more concisely for Python 2:



            from math import fsum
            

            
print(fsum(tup[1] for tup in array) / len(array))






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 22 mins ago

























            answered 2 hours ago









            ruoholaruohola

            1,884420




            1,884420













            • it gives this error : 'int' object is not callable

              – Şevval Kahraman
              1 hour ago











            • @DeveshKumarSingh just need to cast the len to a float for python2: float(len(array)).

              – ruohola
              54 mins ago











            • @ŞevvalKahraman it gives no errors for me with your example array, you probably have a typo somewhere.

              – ruohola
              53 mins ago













            • @ruohola The reason it works for the example is it's 40 / 5 which gives 8 with no remainder. In Python 2, with different numbers, it could truncate the answer.

              – Peter Wood
              49 mins ago











            • @PeterWood it will not truncate anything if you use the float(len(array)) casting when using Python 2. Anyways it shouldn't even matter since this question was for Python 3.x.

              – ruohola
              44 mins ago





















            • it gives this error : 'int' object is not callable

              – Şevval Kahraman
              1 hour ago











            • @DeveshKumarSingh just need to cast the len to a float for python2: float(len(array)).

              – ruohola
              54 mins ago











            • @ŞevvalKahraman it gives no errors for me with your example array, you probably have a typo somewhere.

              – ruohola
              53 mins ago













            • @ruohola The reason it works for the example is it's 40 / 5 which gives 8 with no remainder. In Python 2, with different numbers, it could truncate the answer.

              – Peter Wood
              49 mins ago











            • @PeterWood it will not truncate anything if you use the float(len(array)) casting when using Python 2. Anyways it shouldn't even matter since this question was for Python 3.x.

              – ruohola
              44 mins ago



















            it gives this error : 'int' object is not callable

            – Şevval Kahraman
            1 hour ago





            it gives this error : 'int' object is not callable

            – Şevval Kahraman
            1 hour ago













            @DeveshKumarSingh just need to cast the len to a float for python2: float(len(array)).

            – ruohola
            54 mins ago





            @DeveshKumarSingh just need to cast the len to a float for python2: float(len(array)).

            – ruohola
            54 mins ago













            @ŞevvalKahraman it gives no errors for me with your example array, you probably have a typo somewhere.

            – ruohola
            53 mins ago







            @ŞevvalKahraman it gives no errors for me with your example array, you probably have a typo somewhere.

            – ruohola
            53 mins ago















            @ruohola The reason it works for the example is it's 40 / 5 which gives 8 with no remainder. In Python 2, with different numbers, it could truncate the answer.

            – Peter Wood
            49 mins ago





            @ruohola The reason it works for the example is it's 40 / 5 which gives 8 with no remainder. In Python 2, with different numbers, it could truncate the answer.

            – Peter Wood
            49 mins ago













            @PeterWood it will not truncate anything if you use the float(len(array)) casting when using Python 2. Anyways it shouldn't even matter since this question was for Python 3.x.

            – ruohola
            44 mins ago







            @PeterWood it will not truncate anything if you use the float(len(array)) casting when using Python 2. Anyways it shouldn't even matter since this question was for Python 3.x.

            – ruohola
            44 mins ago




















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