Knights and Knaves question
$begingroup$
You are on a land inhabited by Knights and Knaves. Knights will always tell the truth and knaves always lie.
You meet three inhabitants(A, B, and C), and ask how many of them are knaves. A answers so quietly, so you ask B what A had said. B says that A had said that exactly two of them were knaves. C says B is lying.
Is it possible to know what A is?
Further, what are B and C.
logical-deduction liars
New contributor
$endgroup$
add a comment |
$begingroup$
You are on a land inhabited by Knights and Knaves. Knights will always tell the truth and knaves always lie.
You meet three inhabitants(A, B, and C), and ask how many of them are knaves. A answers so quietly, so you ask B what A had said. B says that A had said that exactly two of them were knaves. C says B is lying.
Is it possible to know what A is?
Further, what are B and C.
logical-deduction liars
New contributor
$endgroup$
$begingroup$
Please don't change your question after someone has answered it. Now the answer references D, E, and F, and makes no sense. I'm editing the answer to match the revised question, but in the future it's best not to make changes that make the answers obsolete ... especially when the changes are superficial like this.
$endgroup$
– Rubio♦
17 mins ago
add a comment |
$begingroup$
You are on a land inhabited by Knights and Knaves. Knights will always tell the truth and knaves always lie.
You meet three inhabitants(A, B, and C), and ask how many of them are knaves. A answers so quietly, so you ask B what A had said. B says that A had said that exactly two of them were knaves. C says B is lying.
Is it possible to know what A is?
Further, what are B and C.
logical-deduction liars
New contributor
$endgroup$
You are on a land inhabited by Knights and Knaves. Knights will always tell the truth and knaves always lie.
You meet three inhabitants(A, B, and C), and ask how many of them are knaves. A answers so quietly, so you ask B what A had said. B says that A had said that exactly two of them were knaves. C says B is lying.
Is it possible to know what A is?
Further, what are B and C.
logical-deduction liars
logical-deduction liars
New contributor
New contributor
edited 55 mins ago
user58804
New contributor
asked 2 hours ago
user58804user58804
212
212
New contributor
New contributor
$begingroup$
Please don't change your question after someone has answered it. Now the answer references D, E, and F, and makes no sense. I'm editing the answer to match the revised question, but in the future it's best not to make changes that make the answers obsolete ... especially when the changes are superficial like this.
$endgroup$
– Rubio♦
17 mins ago
add a comment |
$begingroup$
Please don't change your question after someone has answered it. Now the answer references D, E, and F, and makes no sense. I'm editing the answer to match the revised question, but in the future it's best not to make changes that make the answers obsolete ... especially when the changes are superficial like this.
$endgroup$
– Rubio♦
17 mins ago
$begingroup$
Please don't change your question after someone has answered it. Now the answer references D, E, and F, and makes no sense. I'm editing the answer to match the revised question, but in the future it's best not to make changes that make the answers obsolete ... especially when the changes are superficial like this.
$endgroup$
– Rubio♦
17 mins ago
$begingroup$
Please don't change your question after someone has answered it. Now the answer references D, E, and F, and makes no sense. I'm editing the answer to match the revised question, but in the future it's best not to make changes that make the answers obsolete ... especially when the changes are superficial like this.
$endgroup$
– Rubio♦
17 mins ago
add a comment |
1 Answer
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votes
$begingroup$
It's not possible to know what A is.
C says B is lying. So either C is a knave and B is a knight or C is a knight and B is a knave. Therefore there is one knave among (B,C).
Assume A is a knave. Then there are 2 knaves and A would lie about it. Therefore B is lying about what A said, so A, B are knaves and C is a knight.
Assume A is a knight. Then there is only one knave and B is lying about what A said, so A, C are knights and B is a knave.
In both scenarios B is a knave and C is a knight. A could be either a knight or a knave.
$endgroup$
add a comment |
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1 Answer
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$begingroup$
It's not possible to know what A is.
C says B is lying. So either C is a knave and B is a knight or C is a knight and B is a knave. Therefore there is one knave among (B,C).
Assume A is a knave. Then there are 2 knaves and A would lie about it. Therefore B is lying about what A said, so A, B are knaves and C is a knight.
Assume A is a knight. Then there is only one knave and B is lying about what A said, so A, C are knights and B is a knave.
In both scenarios B is a knave and C is a knight. A could be either a knight or a knave.
$endgroup$
add a comment |
$begingroup$
It's not possible to know what A is.
C says B is lying. So either C is a knave and B is a knight or C is a knight and B is a knave. Therefore there is one knave among (B,C).
Assume A is a knave. Then there are 2 knaves and A would lie about it. Therefore B is lying about what A said, so A, B are knaves and C is a knight.
Assume A is a knight. Then there is only one knave and B is lying about what A said, so A, C are knights and B is a knave.
In both scenarios B is a knave and C is a knight. A could be either a knight or a knave.
$endgroup$
add a comment |
$begingroup$
It's not possible to know what A is.
C says B is lying. So either C is a knave and B is a knight or C is a knight and B is a knave. Therefore there is one knave among (B,C).
Assume A is a knave. Then there are 2 knaves and A would lie about it. Therefore B is lying about what A said, so A, B are knaves and C is a knight.
Assume A is a knight. Then there is only one knave and B is lying about what A said, so A, C are knights and B is a knave.
In both scenarios B is a knave and C is a knight. A could be either a knight or a knave.
$endgroup$
It's not possible to know what A is.
C says B is lying. So either C is a knave and B is a knight or C is a knight and B is a knave. Therefore there is one knave among (B,C).
Assume A is a knave. Then there are 2 knaves and A would lie about it. Therefore B is lying about what A said, so A, B are knaves and C is a knight.
Assume A is a knight. Then there is only one knave and B is lying about what A said, so A, C are knights and B is a knave.
In both scenarios B is a knave and C is a knight. A could be either a knight or a knave.
edited 16 mins ago
Rubio♦
30.8k567189
30.8k567189
answered 2 hours ago
JayJay
2,8742922
2,8742922
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add a comment |
user58804 is a new contributor. Be nice, and check out our Code of Conduct.
user58804 is a new contributor. Be nice, and check out our Code of Conduct.
user58804 is a new contributor. Be nice, and check out our Code of Conduct.
user58804 is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
Please don't change your question after someone has answered it. Now the answer references D, E, and F, and makes no sense. I'm editing the answer to match the revised question, but in the future it's best not to make changes that make the answers obsolete ... especially when the changes are superficial like this.
$endgroup$
– Rubio♦
17 mins ago