Im stuck and having trouble with ¬P ∨ Q Prove: P → Q












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I am having trouble with this problem as I have just started doing logic. Is this the same as P → Q Prove: ¬P ∨ Q?










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    Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org

    – Frank Hubeny
    4 hours ago
















1















I am having trouble with this problem as I have just started doing logic. Is this the same as P → Q Prove: ¬P ∨ Q?










share|improve this question







New contributor




Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 2





    Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org

    – Frank Hubeny
    4 hours ago














1












1








1








I am having trouble with this problem as I have just started doing logic. Is this the same as P → Q Prove: ¬P ∨ Q?










share|improve this question







New contributor




Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












I am having trouble with this problem as I have just started doing logic. Is this the same as P → Q Prove: ¬P ∨ Q?







logic






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Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question







New contributor




Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









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asked 4 hours ago









Hamish DochertyHamish Docherty

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New contributor





Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 2





    Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org

    – Frank Hubeny
    4 hours ago














  • 2





    Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org

    – Frank Hubeny
    4 hours ago








2




2





Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org

– Frank Hubeny
4 hours ago





Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org

– Frank Hubeny
4 hours ago










1 Answer
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In a natural deduction system (if that is what you are using) to prove a conditional, such as is P → Q, you must use a Conditional
Proof.



This takes the form of assuming the antecedent (that is P) aiming to derive the consequent (that is Q) through valid inferences (also using the premises; that is ¬P ∨ Q). Then discharging the assumption allow the deduction of the conditional (that is P → Q).



Now to prove Q from an assumption of P and the premise of ¬P ∨ Q, either use Disjunctive Syllogism, or a Proof by Cases.






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    1 Answer
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    1 Answer
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    active

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    In a natural deduction system (if that is what you are using) to prove a conditional, such as is P → Q, you must use a Conditional
    Proof.



    This takes the form of assuming the antecedent (that is P) aiming to derive the consequent (that is Q) through valid inferences (also using the premises; that is ¬P ∨ Q). Then discharging the assumption allow the deduction of the conditional (that is P → Q).



    Now to prove Q from an assumption of P and the premise of ¬P ∨ Q, either use Disjunctive Syllogism, or a Proof by Cases.






    share|improve this answer




























      2














      In a natural deduction system (if that is what you are using) to prove a conditional, such as is P → Q, you must use a Conditional
      Proof.



      This takes the form of assuming the antecedent (that is P) aiming to derive the consequent (that is Q) through valid inferences (also using the premises; that is ¬P ∨ Q). Then discharging the assumption allow the deduction of the conditional (that is P → Q).



      Now to prove Q from an assumption of P and the premise of ¬P ∨ Q, either use Disjunctive Syllogism, or a Proof by Cases.






      share|improve this answer


























        2












        2








        2







        In a natural deduction system (if that is what you are using) to prove a conditional, such as is P → Q, you must use a Conditional
        Proof.



        This takes the form of assuming the antecedent (that is P) aiming to derive the consequent (that is Q) through valid inferences (also using the premises; that is ¬P ∨ Q). Then discharging the assumption allow the deduction of the conditional (that is P → Q).



        Now to prove Q from an assumption of P and the premise of ¬P ∨ Q, either use Disjunctive Syllogism, or a Proof by Cases.






        share|improve this answer













        In a natural deduction system (if that is what you are using) to prove a conditional, such as is P → Q, you must use a Conditional
        Proof.



        This takes the form of assuming the antecedent (that is P) aiming to derive the consequent (that is Q) through valid inferences (also using the premises; that is ¬P ∨ Q). Then discharging the assumption allow the deduction of the conditional (that is P → Q).



        Now to prove Q from an assumption of P and the premise of ¬P ∨ Q, either use Disjunctive Syllogism, or a Proof by Cases.







        share|improve this answer












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        answered 27 mins ago









        Graham KempGraham Kemp

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